如何改变单个蜂群的位置

Question

我正在绘制一个分组条形图，我在上面叠加了一个群图和误差条。其中一组只有一个条形图，我希望它（带有群和错误条形图）出现在分配给这组条形图的位置的中间。

我设法移动了 bar 和 errorbar，但不确定如何移动 swarm。

这是我的代码：

import seaborn as sns
import matplotlib.pyplot as plt
mypallet = sns.color_palette([(190/256,7/256, 18/256),(127/256, 127/256, 127/256)])
import itertools
import numpy as np

plt.rcParams['figure.figsize'] = 7, 5
tips = sns.load_dataset("tips")
tips[(tips.day=='Thur') & (tips.sex=='Female') ] = np.nan
print(sns.__version__)
print(tips.head())
# Bigger than normal fonts
sns.set(font_scale=1.5)

ax = sns.swarmplot(x="day", y="total_bill", hue="sex",
                 data=tips, split=True, color='k')
ax = sns.barplot(x="day", y="total_bill", hue="sex",
                 data=tips, capsize=0.1, alpha=0.8,
                 errwidth=1.25, ci=None, palette=mypallet)
xcentres = [0.2, 1, 2, 3]
delt = 0.2
xneg = [x-delt for x in xcentres]
xpos = [x+delt for x in xcentres]
xvals = xneg + xpos
xvals.sort()
yvals = tips.groupby(["day", "sex"]).mean().total_bill
yerr = tips.groupby(["day", "sex"]).std().total_bill

(_, caps, _)=ax.errorbar(x=xvals, y=yvals, yerr=yerr, capsize=4,
                         ecolor="red", elinewidth=1.25, fmt='none')
for cap in caps:
    cap.set_markeredgewidth(2)

handles, labels = ax.get_legend_handles_labels()
l = ax.legend(handles[0:2], labels[0:2]) # changed based on 
#sns.ax.ylim([0,60]) #original
ax.set_ylim([0,60]) # adapted from  and change to legend
ax.set_ylabel("Out-of-sample R2") # based on 
ax.set_xlabel("") # based on 

for i, bar in enumerate(ax.patches):
    hatch = '///'
    bar.set_hatch(hatch)
    bar.set_x(bar.get_x() + bar.get_width()/2)
    break

我希望左侧栏的群与栏的中间位置对齐。

Answer 1

让我们使用 matplotlib.collections set_offsets:

import seaborn as sns
import matplotlib.pyplot as plt
mypallet = sns.color_palette([(190/256,7/256, 18/256),(127/256, 127/256, 127/256)])
import itertools
import numpy as np

plt.rcParams['figure.figsize'] = 7, 5
tips = sns.load_dataset("tips")
tips[(tips.day=='Thur') & (tips.sex=='Female') ] = np.nan
print(sns.__version__)
print(tips.head())
# Bigger than normal fonts
sns.set(font_scale=1.5)

ax = sns.swarmplot(x="day", y="total_bill", hue="sex",
                 data=tips, dodge=True, color='k')

#get first patchcollection
c0 = ax.get_children()[0]
x,y = np.array(c0.get_offsets()).T
#Add .2 to x values
xnew=x+.2
offsets = list(zip(xnew,y))
#set newoffsets
c0.set_offsets(offsets)

ax = sns.barplot(x="day", y="total_bill", hue="sex",
                 data=tips, capsize=0.1, alpha=0.8,
                 errwidth=1.25, ci=None, palette=mypallet)
xcentres = [0.2, 1, 2, 3]
delt = 0.2
xneg = [x-delt for x in xcentres]
xpos = [x+delt for x in xcentres]
xvals = xneg + xpos
xvals.sort()
yvals = tips.groupby(["day", "sex"]).mean().total_bill
yerr = tips.groupby(["day", "sex"]).std().total_bill

(_, caps, _)=ax.errorbar(x=xvals, y=yvals, yerr=yerr, capsize=4,
                         ecolor="red", elinewidth=1.25, fmt='none')
for cap in caps:
    cap.set_markeredgewidth(2)


handles, labels = ax.get_legend_handles_labels()
l = ax.legend(handles[0:2], labels[0:2]) # changed based on 
#sns.ax.ylim([0,60]) #original
ax.set_ylim([0,60]) # adapted from  and change to legend
ax.set_ylabel("Out-of-sample R2") # based on 
ax.set_xlabel("") # based on 

for i, bar in enumerate(ax.patches):
    hatch = '///'
    bar.set_hatch(hatch)
    bar.set_x(bar.get_x() + bar.get_width()/2)
    break

输出：

如何改变单个蜂群的位置

How to change the position of a single swarm group

python

matplotlib

seaborn

swarmplot