mysql

Question

我有以下结果集：

req_id |  p_id  | ai_result  |  hash | sku
1      |  4     | Match      |  XAN  | HOW
1      |  4     | Match      |  HXN  | HOW
1      |  4     | Non Match  |  123  | HOW

我需要有以下输出

sku  | matched  |  non_matched
HOW  | XAN, HXN |  123

这是我所能得到的：

SELECT sku, GROUP_CONCAT(hash) AS hash
FROM `sku_match` 
GROUP BY req_id, p_id

如何根据ai_result列区分行并分开放置。类似于 GROUP_CONCAT(hash) AS matched, GROUP_CONCAT(hash) AS non_matched?

Answer 1

尝试使用条件聚合：

SELECT
    sku,
    GROUP_CONCAT(CASE WHEN ai_result = 'Match' THEN hash END) AS matched,
    GROUP_CONCAT(CASE WHEN ai_result = 'Non Match' THEN hash END) AS non_matched
FROM sku_match
GROUP BY
    sku;

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