如何获取链接到外键值的 InnoDB table 名称？

Question

我有多个 table 链接到 'address' table，其中 ADDRESS_ID 是主键。表 A、B、C... 可能有 address_ID 值，也可能没有。是否有一个查询，我可以在地址 table 中获得具有给定 ADDRESS_ID 的 table 名称？请注意，这不是 'address' table 中给定列的 table 名称。如果地址 table 中的给定 Address_ID 值 已在其他 table 中引用，我需要 table 名称。（我不知道所有可能引用了 address_id 的 table。）

Address table 
ADDRESS_ID (PK) |   STREET ADDRESS_1   |   STREET_ADDRESS_2  |   CITY  |  ZIPCODE    


Table A
A_ID  |  ADDRESS_ID (FK) |  FIELD _1  |   FIELD_2

Table B
B_ID  |  ADDRESS_ID (FK)|  FIELD _!  |  FIELD_2

Table C
B_ID  |  ADDRESS_ID (FK) |  FIELD _! |  FIELD_2

更多table秒......

这是我试过的：

SELECT * FROM information_schema.TABLE_CONSTRAINTS 
WHERE 
information_schema.TABLE_CONSTRAINTS.CONSTRAINT_TYPE = 'FOREIGN KEY' AND
TABLE_CONSTRAINTS.TABLE_SCHEMA = 'flower_db' AND
TABLE_CONSTRAINTS.TABLE_NAME = 'address';

但这并不支持我真正想要的。

Answer 1

 SELECT 'TableA' as Table_Has_Address       
 FROM TableA
 GROUP BY ADDRESS_ID
 HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0

 UNION ALL

 SELECT 'TableB' as Table_Has_Address       
 FROM TableB
 GROUP BY ADDRESS_ID
 HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0

 UNION ALL

 SELECT 'TableC' as Table_Has_Address       
 FROM TableC
 GROUP BY ADDRESS_ID
 HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0

Answer 2

SELECT *
    FROM information_schema.REFERENTIAL_CONSTRAINTS
    WHERE REFERENCED_TABLE_NAME = 'address'

（根据需要调整查询）

如何获取链接到外键值的 InnoDB table 名称？

How to get InnoDB table names that are linked to foreign key value?

mysql

innodb