具有位域大小的结构
Structure with bit-fields size
我尝试使用具有不同大小位域的结构。使用的总位数为 64。但是,当我检查结构大小时,我得到 11 而不是预期的 8。通过尝试分解结构,我发现差异来自 day 字段。如果我打包每一位以获得 8 位包,则 day 字段在 month 的 "end" 和 [= 小时 的 26=]。我不知道这是否是一个好方法。谁能给我解释一下?
typedef unsigned char uint8_t;
typedef struct frameHeader_t
{
uint8_t encryption : 2;
uint8_t frameVersion : 2;
uint8_t probeType : 4;
uint8_t dataType : 5;
uint8_t measurePeriod : 3;
uint8_t remontePerdiod : 4;
uint8_t nbrMeasure : 2;
uint8_t year : 7;
uint8_t month : 4;
uint8_t day : 5;
uint8_t hour : 5;
uint8_t minute : 6;
uint8_t second : 6;
uint8_t randomization : 5;
uint8_t status : 4;
}FrameHeader;
int main()
{
FrameHeader my_frameHeader;
printf("%d\n", sizeof(FrameHeader));
return 0;
}
如果你 运行 通过 pahole
工具,你应该得到解释:
struct frameHeader_t {
uint8_t encryption:2; /* 0: 6 1 */
uint8_t frameVersion:2; /* 0: 4 1 */
uint8_t probeType:4; /* 0: 0 1 */
uint8_t dataType:5; /* 1: 3 1 */
uint8_t measurePeriod:3; /* 1: 0 1 */
uint8_t remontePerdiod:4; /* 2: 4 1 */
uint8_t nbrMeasure:2; /* 2: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t year:7; /* 3: 1 1 */
/* XXX 1 bit hole, try to pack */
uint8_t month:4; /* 4: 4 1 */
/* XXX 4 bits hole, try to pack */
uint8_t day:5; /* 5: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t hour:5; /* 6: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t minute:6; /* 7: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t second:6; /* 8: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t randomization:5; /* 9: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t status:4; /* 10: 4 1 */
/* size: 11, cachelines: 1, members: 15 */
/* bit holes: 8, sum bit holes: 20 bits */
/* bit_padding: 4 bits */
/* last cacheline: 11 bytes */
};
您正在使用 uint8_t
作为基本类型,因此字段被填充为 8 位组。
您应该能够完全消除填充,通过使用 unsigned long long
/uint_least64_t
(至少 64 位大)作为基本类型,比 __attribute((packed))
更便携位域,但从技术上讲,不保证支持位域的 non-int/non-unsigned-int 基本类型,但您可以在稍微重组位域后使用 unsigned
(C 标准至少保证 16 位),例如:
typedef struct frameHeader_t
{
//16
unsigned year : 7;
unsigned randomization : 5;
unsigned month : 4;
//16
unsigned second : 6;
unsigned minute : 6;
unsigned status : 4;
//16
unsigned hour : 5;
unsigned dataType : 5;
unsigned probeType : 4;
unsigned encryption : 2;
//16
unsigned day : 5;
unsigned remontePerdiod : 4;
unsigned measurePeriod : 3;
unsigned nbrMeasure : 2;
unsigned frameVersion : 2;
}FrameHeader;
//should be an unpadded 8 bytes as long as `unsigned` is 16,
//32, or 64 bits wide (I don't know of a platform where it isn't)
(不能保证填充或缺少填充,但除非有必要,否则我从未见过插入它的实现。)
为了避免打包魔术,我通常使用具有相同大小的固定大小无符号类型
typedef struct frameHeader_t
{
uint64_t encryption : 2;
uint64_t frameVersion : 2;
uint64_t probeType : 4;
uint64_t dataType : 5;
uint64_t measurePeriod : 3;
uint64_t remontePerdiod : 4;
uint64_t nbrMeasure : 2;
uint64_t year : 7;
uint64_t month : 4;
uint64_t day : 5;
uint64_t hour : 5;
uint64_t minute : 6;
uint64_t second : 6;
uint64_t randomization : 5;
uint64_t status : 4;
}FrameHeader;
我尝试使用具有不同大小位域的结构。使用的总位数为 64。但是,当我检查结构大小时,我得到 11 而不是预期的 8。通过尝试分解结构,我发现差异来自 day 字段。如果我打包每一位以获得 8 位包,则 day 字段在 month 的 "end" 和 [= 小时 的 26=]。我不知道这是否是一个好方法。谁能给我解释一下?
typedef unsigned char uint8_t;
typedef struct frameHeader_t
{
uint8_t encryption : 2;
uint8_t frameVersion : 2;
uint8_t probeType : 4;
uint8_t dataType : 5;
uint8_t measurePeriod : 3;
uint8_t remontePerdiod : 4;
uint8_t nbrMeasure : 2;
uint8_t year : 7;
uint8_t month : 4;
uint8_t day : 5;
uint8_t hour : 5;
uint8_t minute : 6;
uint8_t second : 6;
uint8_t randomization : 5;
uint8_t status : 4;
}FrameHeader;
int main()
{
FrameHeader my_frameHeader;
printf("%d\n", sizeof(FrameHeader));
return 0;
}
如果你 运行 通过 pahole
工具,你应该得到解释:
struct frameHeader_t {
uint8_t encryption:2; /* 0: 6 1 */
uint8_t frameVersion:2; /* 0: 4 1 */
uint8_t probeType:4; /* 0: 0 1 */
uint8_t dataType:5; /* 1: 3 1 */
uint8_t measurePeriod:3; /* 1: 0 1 */
uint8_t remontePerdiod:4; /* 2: 4 1 */
uint8_t nbrMeasure:2; /* 2: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t year:7; /* 3: 1 1 */
/* XXX 1 bit hole, try to pack */
uint8_t month:4; /* 4: 4 1 */
/* XXX 4 bits hole, try to pack */
uint8_t day:5; /* 5: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t hour:5; /* 6: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t minute:6; /* 7: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t second:6; /* 8: 2 1 */
/* XXX 2 bits hole, try to pack */
uint8_t randomization:5; /* 9: 3 1 */
/* XXX 3 bits hole, try to pack */
uint8_t status:4; /* 10: 4 1 */
/* size: 11, cachelines: 1, members: 15 */
/* bit holes: 8, sum bit holes: 20 bits */
/* bit_padding: 4 bits */
/* last cacheline: 11 bytes */
};
您正在使用 uint8_t
作为基本类型,因此字段被填充为 8 位组。
您应该能够完全消除填充,通过使用 unsigned long long
/uint_least64_t
(至少 64 位大)作为基本类型,比 __attribute((packed))
更便携位域,但从技术上讲,不保证支持位域的 non-int/non-unsigned-int 基本类型,但您可以在稍微重组位域后使用 unsigned
(C 标准至少保证 16 位),例如:
typedef struct frameHeader_t
{
//16
unsigned year : 7;
unsigned randomization : 5;
unsigned month : 4;
//16
unsigned second : 6;
unsigned minute : 6;
unsigned status : 4;
//16
unsigned hour : 5;
unsigned dataType : 5;
unsigned probeType : 4;
unsigned encryption : 2;
//16
unsigned day : 5;
unsigned remontePerdiod : 4;
unsigned measurePeriod : 3;
unsigned nbrMeasure : 2;
unsigned frameVersion : 2;
}FrameHeader;
//should be an unpadded 8 bytes as long as `unsigned` is 16,
//32, or 64 bits wide (I don't know of a platform where it isn't)
(不能保证填充或缺少填充,但除非有必要,否则我从未见过插入它的实现。)
为了避免打包魔术,我通常使用具有相同大小的固定大小无符号类型
typedef struct frameHeader_t
{
uint64_t encryption : 2;
uint64_t frameVersion : 2;
uint64_t probeType : 4;
uint64_t dataType : 5;
uint64_t measurePeriod : 3;
uint64_t remontePerdiod : 4;
uint64_t nbrMeasure : 2;
uint64_t year : 7;
uint64_t month : 4;
uint64_t day : 5;
uint64_t hour : 5;
uint64_t minute : 6;
uint64_t second : 6;
uint64_t randomization : 5;
uint64_t status : 4;
}FrameHeader;