每 22 个字符添加一个 enter to string，等待 space

Question

我试图让我的代码每 22 个字符插入一个 \n 到我的代码中，但是如果第 22 个字符不是 space 它会等到有一个然后插入 \n那里。

我曾尝试在 Whosebug 上查找过去一个小时的一些代码，但大多数似乎都因一些更改而中断，因为它们是专门针对该问题而设计的。

这是我试过的一些代码

count = 0
s = "I learned to recognise the through and primitive duality of man; I saw that, of the two natures that contended in the field of my consciousness, even if I could rightly be said to be either, it was only because I was radically both"
newS = ""
enterASAP = False
while True:
    count += 1
    if enterASAP == True and s[count-1] == " ":
        newS = (s[:count] + "\n" + s[count:])
    if count % 22 == 0:
        if s[count-1] == " ":
            newS = (s[:count] + "\n" + s[count:])
        else:
            enterASAP = True
    if count == len(s):
        print(newS)
        print("Done")
        break

我希望它生成类似
的文本 I learned to recognise the thorough and primitive
.......
请注意，它等待 space，然后计数从 the 重置为 primitive，而不是添加代码等待 [=] 的 5 个额外字母30=].

我的代码生成了它开头的确切字符串。这让我感到困惑

Answer 1

正如评论中所讨论的那样，带有 textwrap (doc) 的版本：

import textwrap

s = "I learned to recognise the through and primitive duality of man; I saw that, of the two natures that contended in the field of my consciousness, even if I could rightly be said to be either, it was only because I was radically both"

print('\n'.join(textwrap.wrap(s, 22)))

打印：

I learned to recognise
the through and
primitive duality of
man; I saw that, of
the two natures that
contended in the field
of my consciousness,
even if I could
rightly be said to be
either, it was only
because I was
radically both

每 22 个字符添加一个 enter to string，等待 space

Add an enter to string every 22 characters, waiting until a space

python

enter