Google Cloud Build 子构建

Question

每个子目录可以有多个 cloudbuild.yaml 文件吗？

例如：

my-app:
  - service1
    - cloudbuild.yaml
  - service2
    - cloudbuild.yaml
  cloudbuild.yaml

Answer 1

是的，绝对是！您是否尝试从 my-app/cloudbuild.yaml 初始化 service1 和 service2 的构建？

使用 meta 配置初始化其他构建的示例：https://github.com/GoogleCloudPlatform/cloudbuild-integration-testing/blob/master/cloudbuild.meta.yaml

这里是 cloudbuild.meta.yaml 根据您的示例构建的：

steps:
- id: 'build service1'
  name: 'gcr.io/cloud-builders/gcloud'
  args: ['builds', 'submit', '--config service1/cloudbuild.yaml']
  waitFor: ['-'] #start in parallel
- id: 'build service2'
  name: 'gcr.io/cloud-builders/gcloud'
  args: ['builds', 'submit', '--config service2/cloudbuild.yaml']
  waitFor: ['-'] # start in parallel

Answer 2

答案基本正确。这将不起作用，因为您忘记包含“.”，它告诉您上传并构建当前目录。包含 sub/child cloudbuild.yaml 的正确方法是：

# Include cloudbuild sub step
- name: 'gcr.io/cloud-builders/gcloud'
  args:
  - 'builds'
  - 'submit'
  - '.'
  - '--config'
  - 'cloudbuild.yaml'

Google Cloud Build 子构建

Google Cloud Build sub builds

google-cloud-platform

google-cloud-build