如何将 MySQL JSON 数组转换为逗号分隔的字符串

Question

我在一列中有以下 phone 个数字：

["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]

我怎样才能得到这样的信息：

+63(02)3647766,+63(02)5467329,+63(02)8555522,+63(02)3642403

Answer 1

我认为这是最唯一的 MySQL 干净的方法，至少对于 MySQL 8

以下的版本

查询

SET SESSION group_concat_max_len = @@max_allowed_packet;

SELECT
  GROUP_CONCAT(
     JSON_UNQUOTE(
       JSON_EXTRACT(records.json, CONCAT('$[', number_generator.number , ']'))
     )
  )                    

FROM (

  SELECT 
   @row := @row + 1 AS number
  FROM (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION   SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row1
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION  SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row2
  CROSS JOIN (
    SELECT @row := -1 
  ) init_user_params 
) AS number_generator
CROSS JOIN (


SELECT 
    json
  , JSON_LENGTH(records.json) AS json_array_length    
FROM (

  SELECT 
   '["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]' AS json
  FROM 
   DUAL  
) AS records

) AS records 
WHERE
    number BETWEEN 0 AND  json_array_length - 1

结果

| GROUP_CONCAT(
     JSON_UNQUOTE(
       JSON_EXTRACT(records.json, CONCAT('$[', number_generator.number , ']'))
     )
  ) |
| -------------------------------------------------------------------------------------------------------------------------- |
| +63(02)3647766,+63(02)5467329,+63(02)8555522,+63(02)3642403                                                                |

见demo

Have you heard of JSON_TABLE()? – oysteing

我有，我不认为每个人都已经在 MySQL 8 上，但我也添加它是为了完整性。

MySQL 8.0 仅查询

SET SESSION group_concat_max_len = @@max_allowed_packet;

SELECT 
 GROUP_CONCAT(item)
FROM JSON_TABLE(
     '["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]'
   , "$[*]"

   COLUMNS (
       rowid FOR ORDINALITY
     , item VARCHAR(100) PATH "$"   
   )
) AS json_parsed

结果

| GROUP_CONCAT(item)                                          |
| ----------------------------------------------------------- |
| +63(02)3647766,+63(02)5467329,+63(02)8555522,+63(02)3642403 |

见demo

REPLACE() 嵌套方法比较混乱，但应该适用于所有 MySQL 版本。

SELECT 
 REPLACE(
   REPLACE(
      REPLACE(
       '["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]'
       , '['
       , ''
     )
     , ']'
     , ''
   )
   , '"'
   , ''
 )

结果

| REPLACE(
   REPLACE(
      REPLACE(
       '["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]'
       , '['
       , ''
     )
     , ']'
     , ''
   )
   , '"'
   , ''
 ) |
| --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |
| +63(02)3647766, +63(02)5467329, +63(02)8555522, +63(02)3642403                                                                                                                                      |

见demo

Answer 2

如果这不是您要执行的查询，这是一个简单的函数，您可以传递数组并取回字符串。

$data  = ["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"];
function MakeAstring($data){
     $array_with_comma = array();
    $last_key = end(array_keys($data));
  foreach($data as $key =>  $number)
   {
     $string .= $number.($key != $last_key ? ',': '');
   }
  return $string;
}
echo MakeAstring($data);

Answer 3

所以如果你有 replace replace 替换功能。它超级酷而且简单。如果要构建逗号分隔的 varchar 值，请使用以下内容；

@json_array = ["value1", "value2"]

select replace(replace(replace(json_extract(@json_array, '$'), '"', '\''), '[', ''), ']', '');

但是如果你想构建数字然后使用

select replace(replace(replace(json_extract(@json_array, '$'), '"', ''), '[', ''), ']', '');enter code here

Answer 4

最适合所有MySQL版本的解决方案是：

SELECT
    REPLACE(
        REPLACE(
            REPLACE(
                records.json,
                '[',
                ''
            ),
            ']',
            ''
        ),
        '"',
        ''
    ) AS comma_separated
FROM (
    SELECT
        '["+63(02)3647766", "+63(02)5467329", "+63(02)8555522", "+63(02)3642403"]' AS json
) AS records;

看起来很重，但它很有魅力。

如何将 MySQL JSON 数组转换为逗号分隔的字符串

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