如何使用 firebase 函数从外部 url(PLACES API) 抓取 json 文件

Question

所以，我想使用云功能从我的应用程序向 Firebase 发送请求，然后处理进程 url 并从 api

位置发回 JSON 文件

我已经有了DONE/HAVE=> 在控制台中设置项目并获取 firebase CLI 后创建了一个云函数，如下所示

关注您的评论后这是我的完整功能代码：

const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
const rp = require('request-promise');

exports.fetch = functions.https.onCall((req, res) => {

    const url = req.url + '&key=MY_API_KEY';
    var options = {
        uri: url, // Automatically parses the JSON string in the response
        json: true
    };  

    rp(options)
    .then(result => {
        console.log('Get response:' + response.statusCode);
        return res.type('application/json').send(result);
    }).catch(err => {
        // API call failed...
        return res.send({'Error': err});
    });

})

并在 java class 中传递了这样的值

     private Task<String> addMessage(String url) {
            // Create the arguments to the callable function.
            Map<String, Object> data = new HashMap<>();
            data.put("url", url);///PASSING VALUES HERE
            return mFunctions
                    .getHttpsCallable("fetch")
                    .call(data)
                    .continueWith(task -> 
(String) Objects.requireNonNull(task.getResult()).getData());
        }

现在我的问题是在使用 firebase CLI 部署新功能代码时我收到 16:8 error Each then() should return a value or throw promise/always-return 作为错误

谁能指导我..,

URL 会像这样： https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=17.4369681,78.4473887&radius=5000&type=airport&sensor=true&key=MY_KEY

这是来自控制台的日志详细信息

2019-07-05T10:06:35.025308453Z D fetch: Function execution started
2019-07-05T10:06:35.265840608Z D fetch: Function execution took 241 ms, finished with status code: 200
2019-07-05T10:06:45.162Z I fetch: Get response:undefined
2019-07-05T10:06:46.062Z E fetch: Unhandled rejection
2019-07-05T10:06:46.062Z E fetch: TypeError: res.send is not a function
    at rp.then.catch.err (/srv/index.js:22:14)
    at bound (domain.js:301:14)
    at runBound (domain.js:314:12)
    at tryCatcher (/srv/node_modules/bluebird/js/release/util.js:16:23)
    at Promise._settlePromiseFromHandler (/srv/node_modules/bluebird/js/release/promise.js:517:31)
    at Promise._settlePromise (/srv/node_modules/bluebird/js/release/promise.js:574:18)
    at Promise._settlePromise0 (/srv/node_modules/bluebird/js/release/promise.js:619:10)
    at Promise._settlePromises (/srv/node_modules/bluebird/js/release/promise.js:695:18)
    at _drainQueueStep (/srv/node_modules/bluebird/js/release/async.js:138:12)
    at _drainQueue (/srv/node_modules/bluebird/js/release/async.js:131:9)
    at Async._drainQueues (/srv/node_modules/bluebird/js/release/async.js:147:5)
    at Immediate.Async.drainQueues (/srv/node_modules/bluebird/js/release/async.js:17:14)
    at runCallback (timers.js:810:20)
    at tryOnImmediate (timers.js:768:5)
    at processImmediate [as _immediateCallback] (timers.js:745:5)

Answer 1

您应该在 Cloud Function 中使用 promises 来处理异步任务（例如对 URL 的调用）。默认情况下 request 不会 return promises，所以你需要为请求使用接口包装器，比如 request-promise.

以下改编应该可以解决问题：

const rp = require('request-promise');

exports.fetch = functions.https.onCall((req, res) => {

  const url = req.url + '&key=MY_API_KEY';
  console.log(url);

  var options = {
    uri: url,
    json: true // Automatically parses the JSON string in the response
  };

  rp(options)
    .then(response => {
      console.log('Get response: ' + response.statusCode);
      res.send(response);
    })
    .catch(err => {
      // API call failed...
      res.status(500).send('Error': err);
    });

})

Answer 2

这对我有用。在 promise 之前使用 return return 是 promise 的结果，我们需要在使用 functions.https.onCall 和 [= 时使用 return 13=] 当使用 functions.https.onRequest 时，我花了 3 天时间才得到它，当你的 url return 是 json，这只会让事情变得复杂

const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
const rp = require('request-promise');

exports.fetch = functions.https.onCall((req, res) => {

    const url = req.url + '&key=MY_API_KEY';
    var options = {
        uri: url, // Automatically parses the JSON string in the response
    };

    return rp(options)
    .then(result => {
        console.log('here is response: ' + result);
        return result;
    }).catch(err => {
        // API call failed...
        return err;
    });

})

如何使用 firebase 函数从外部 url(PLACES API) 抓取 json 文件

How to grab json file from external url(PLACES API) using firebase functions

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