有没有办法从 4x4 矩阵计算 X 和 Y 轴上的 3D 旋转

Question

首先，我根本不是数学专家。请容忍我的数学错误并在必要时纠正我，我很乐意学习。

我有一个立方体，它使用 css 变换动画旋转：matrix3d(4x4)。我还可以手动旋转立方体，将用户操作转换为相同的 matrix3d 转换。

我想要的是一个旋转的立方体 css 当用户停止交互时从用户离开的地方开始。这是我通过获取立方体的变换 matrix3d 值并使用乘法动态设置 css 的关键帧而成功完成的事情。

但是，当用户开始与立方体交互时，立方体会跳转到其最后已知的手动旋转点并从那里继续，因为我不知道如何从 4x4 矩阵获取 X 轴和 Y 轴上的旋转.

我目前正在使用以下库 Rematrix，它帮助我从手动轮换到 css 轮换，如上所述。

我一直在研究关于 Euler 的文章，以及如何从 Euler 到矩阵，反之亦然，但正如我之前提到的，我认为这是我缺乏数学知识阻碍我前进的地方。我似乎无法弄清楚。

作为参考，以下是我阅读过的一些文章，试图解决我的问题。

最后一个来源对我来说最有意义，但如果我是正确的，在这种情况下没有用，因为它是关于 2D 转换，而不是 3D。

我通过以下方式获取当前的 matrix3d:

const style = getComputedStyle(this.element).transform
const matrix = Rematrix.parse(style)

对于手动旋转，我使用基于用户鼠标位置（positionY、positionX）的矩阵乘法。

const r1 = Rematrix.rotateX(this.positionY)
const r2 = Rematrix.rotateY(this.positionX)

const transform = [r1, r2].reduce(Rematrix.multiply)

this.element.style[userPrefix.js + 'Transform'] = Rematrix.toString(transform)

从手动到 css 旋转我使用以下函数：

const setCssAnimationKeyframes = (lastTransform, animationData) => {
  const rotationIncrement = 90

  let matrixes = []

  for (let i = 0; i < 5; i++) {
    const rX = Rematrix.rotateX(rotationIncrement * i)
    const rY = Rematrix.rotateY(rotationIncrement * i)

    const matrix = [lastTransform, rX, rY].reduce(Rematrix.multiply);

    matrixes.push(matrix)
  }

  animationData.innerHTML = `
    @keyframes rotateCube {
      0% {
        transform: ${Rematrix.toString(matrixes[0])};
      }
      25% {
        transform: ${Rematrix.toString(matrixes[1])};
      }
      50% {
        transform: ${Rematrix.toString(matrixes[2])};
      }
      75% {
        transform: ${Rematrix.toString(matrixes[3])}};
      }
      100% {
        transform: ${Rematrix.toString(matrixes[4])};
      }
    }
  `;
}

请提供任何有用信息的答案或评论。尽管非常欢迎，但我不希望您提供完整的代码示例。非常感谢任何形式的有用信息。

Answer 1

第一次阅读：

因为我使用那里的术语。

嗯，我懒得把所有东西都等同于我的环境，但基于此：

Computing Euler angles from a rotation matrix

对于任何旋转顺序，m 的结果 3D 旋转子矩阵将始终具有这些热量：

(+/-)sin(a)
(+/-)sin(b)cos(a)
(+/-)cos(b)cos(a)
(+/-)sin(c)cos(a)
(+/-)cos(c)cos(a)

只有它们的符号和位置会随着变换顺序和约定而改变。因此，要识别它们，请执行以下操作：

先设置一些非平凡的欧拉角

它们的 |sin| , |cos| 值必须不同，所以 6 个值中的 none 将相同，否则这将不起作用!!!

我选择了这些：
```
ex = 10 [deg]
ey = 20 [deg]
ez = 30 [deg]
```

计算旋转矩阵m

因此按顺序对单位矩阵应用 3 次欧拉旋转。在我的设置中，结果矩阵如下所示：

double m[16] = 
 { 
  0.813797652721405, 0.543838143348694,-0.204874128103256, 0, // Xx,Xy,Xz,0.0
 -0.469846308231354, 0.823172926902771, 0.318795770406723, 0, // Yx,Yy,Yz,0.0
  0.342020153999329,-0.163175910711288, 0.925416529178619, 0, // Zx,Zy,Zz,0.0
  0                , 0                , 0                , 1  // Ox,Oy,Oz,1.0
 };

请注意，我使用的是 OpenGL 约定，基向量 X,Y,Z 和原点 O 由矩阵的行表示，矩阵是直接的。

识别(+/-)sin(a)热

a 可以是任何欧拉角，所以打印 sin 个欧拉角：
```
sin(ex) = 0.17364817766693034885171662676931
sin(ey) = 0.34202014332566873304409961468226
sin(ez) = 0.5
```
现在看到 m[8] = sin(ey) 所以我们找到了我们的热……现在我们知道了：
```
ey = a = asin(m[8]);
```

识别(+/-)???(?)*cos(a)热量

简单地为尚未使用的角度打印 cos(?)*cos(ey)。所以如果 ey 是 20 度，我打印 10 和 30 度 ...

sin(10 deg)*cos(20 deg) = 0.16317591116653482557414168661534
cos(10 deg)*cos(20 deg) = 0.92541657839832335306523309767123
sin(30 deg)*cos(20 deg) = 0.46984631039295419202705463866237
cos(30 deg)*cos(20 deg) = 0.81379768134937369284469321724839

当我们再次查看 m 时，我们可以交叉匹配：

sin(ex)*cos(ey) = 0.16317591116653482557414168661534 = -m[9]
cos(ex)*cos(ey) = 0.92541657839832335306523309767123 = +m[10]
sin(ez)*cos(ey) = 0.46984631039295419202705463866237 = -m[4]
cos(ez)*cos(ey) = 0.81379768134937369284469321724839 = +m[0]

据此我们可以计算角度...

sin(ex)*cos(ey) = -m[ 9]
cos(ex)*cos(ey) = +m[10]
sin(ez)*cos(ey) = -m[ 4]
cos(ez)*cos(ey) = +m[ 0]
------------------------
sin(ex) = -m[ 9]/cos(ey)
cos(ex) = +m[10]/cos(ey)
sin(ez) = -m[ 4]/cos(ey)
cos(ez) = +m[ 0]/cos(ey)

所以最后：

---------------------------------------------
ey = asin(m[8]);
ex = atan2( -m[ 9]/cos(ey) , +m[10]/cos(ey) )
ez = atan2( -m[ 4]/cos(ey) , +m[ 0]/cos(ey) )
---------------------------------------------

就是这样。如果你有不同的 layout/conventions/transform 顺序，这种方法仍然有效......只有索引和符号会改变。这里是小 C++/VCL OpenGL 示例，我在 (X,Y,Z order):

上测试了这个

//---------------------------------------------------------------------------
#include <vcl.h>
#include <math.h>
#pragma hdrstop
#include "Unit1.h"
#include "gl_simple.h"
//---------------------------------------------------------------------------
#pragma package(smart_init)
#pragma resource "*.dfm"
TForm1 *Form1;
bool _redraw=true;                  // need repaint?

//---------------------------------------------------------------------------
double m[16]=               // uniform 4x4 matrix
    {
    1.0,0.0,0.0,0.0,        // Xx,Xy,Xz,0.0
    0.0,1.0,0.0,0.0,        // Yx,Yy,Yz,0.0
    0.0,0.0,1.0,0.0,        // Zx,Zy,Zz,0.0
    0.0,0.0,0.0,1.0         // Ox,Oy,Oz,1.0
    };
double e[3]={0.0,0.0,0.0};  // euler angles x,y,z order
//---------------------------------------------------------------------------
const double deg=M_PI/180.0;
const double rad=180.0/M_PI;
void matrix2euler(double *e,double *m)
    {
    double c;
    e[1]=asin(+m[ 8]);
    c=cos(e[1]); if (fabs(c>1e-20)) c=1.0/c; else c=0.0;
    e[0]=atan2(-m[ 9]*c,m[10]*c);
    e[2]=atan2(-m[ 4]*c,m[ 0]*c);
    }
//---------------------------------------------------------------------------
void gl_draw()
    {
    _redraw=false;
    glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);

    glMatrixMode(GL_PROJECTION);
//  glLoadIdentity();
    glMatrixMode(GL_TEXTURE);
    glLoadIdentity();
    glMatrixMode(GL_MODELVIEW);
    glLoadIdentity();
    glTranslated(0.0,0.0,-10.0);    // some distance from camera ...

    glDisable(GL_DEPTH_TEST);
    glDisable(GL_TEXTURE_2D);

    int i;
    // draw source matrix:
    glMatrixMode(GL_MODELVIEW);
    glPushMatrix();
    glTranslated(-1.0,0.0,0.0); // source matrix on the left
    glMultMatrixd(m);
    glBegin(GL_LINES);
    glColor3f(1.0,0.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3d(1.0,0.0,0.0);
    glColor3f(0.0,1.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3d(0.0,1.0,0.0);
    glColor3f(0.0,0.0,1.0); glVertex3d(0.0,0.0,0.0); glVertex3d(0.0,0.0,1.0);
    glEnd();
    glPopMatrix();

    // draw source matrix:
    glMatrixMode(GL_MODELVIEW);
    glPushMatrix();
    glTranslated(m[12],m[13],m[14]);    // source matrix in the middle
    glBegin(GL_LINES);
    glColor3f(1.0,0.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3dv(m+0);
    glColor3f(0.0,1.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3dv(m+4);
    glColor3f(0.0,0.0,1.0); glVertex3d(0.0,0.0,0.0); glVertex3dv(m+8);
    glEnd();
    glPopMatrix();

    // draw euler angles
    matrix2euler(e,m);
    glMatrixMode(GL_MODELVIEW);
    glPushMatrix();
    glTranslated(+1.0,0.0,0.0); // euler angles on the right
    glRotated(e[0]*rad,1.0,0.0,0.0);
    glRotated(e[1]*rad,0.0,1.0,0.0);
    glRotated(e[2]*rad,0.0,0.0,1.0);
    glBegin(GL_LINES);
    glColor3f(1.0,0.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3d(1.0,0.0,0.0);
    glColor3f(0.0,1.0,0.0); glVertex3d(0.0,0.0,0.0); glVertex3d(0.0,1.0,0.0);
    glColor3f(0.0,0.0,1.0); glVertex3d(0.0,0.0,0.0); glVertex3d(0.0,0.0,1.0);
    glEnd();
    glPopMatrix();

//  glFlush();
    glFinish();
    SwapBuffers(hdc);
    }
//---------------------------------------------------------------------------
__fastcall TForm1::TForm1(TComponent* Owner):TForm(Owner)
    {
    gl_init(Handle);
    glMatrixMode(GL_MODELVIEW);
    glLoadIdentity();
    glRotated(10.0,1.0,0.0,0.0);
    glRotated(20.0,0.0,1.0,0.0);
    glRotated(30.0,0.0,0.0,1.0);
    glGetDoublev(GL_MODELVIEW_MATRIX,m);
    }
//---------------------------------------------------------------------------
void __fastcall TForm1::FormDestroy(TObject *Sender)
    {
    gl_exit();
    }
//---------------------------------------------------------------------------
void __fastcall TForm1::FormPaint(TObject *Sender)
    {
    gl_draw();
    }
//---------------------------------------------------------------------------
void __fastcall TForm1::Timer1Timer(TObject *Sender)
    {
    if (_redraw) gl_draw();
    }
//---------------------------------------------------------------------------
void __fastcall TForm1::FormResize(TObject *Sender)
    {
    gl_resize(ClientWidth,ClientHeight);
    _redraw=true;
    }
//---------------------------------------------------------------------------
void __fastcall TForm1::FormKeyDown(TObject *Sender, WORD &Key, TShiftState Shift)
    {
//  Caption=Key;
    const double da=5.0;
    if (Key==37){ _redraw=true; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixd(m); glRotated(+da,0.0,1.0,0.0); glGetDoublev(GL_MODELVIEW_MATRIX,m); glPopMatrix(); }
    if (Key==39){ _redraw=true; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixd(m); glRotated(-da,0.0,1.0,0.0); glGetDoublev(GL_MODELVIEW_MATRIX,m); glPopMatrix(); }
    if (Key==38){ _redraw=true; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixd(m); glRotated(+da,1.0,0.0,0.0); glGetDoublev(GL_MODELVIEW_MATRIX,m); glPopMatrix(); }
    if (Key==40){ _redraw=true; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixd(m); glRotated(-da,1.0,0.0,0.0); glGetDoublev(GL_MODELVIEW_MATRIX,m); glPopMatrix(); }
    }
//---------------------------------------------------------------------------

其中唯一重要的东西是 matrix2euler 函数，它按 x,y,z 顺序将矩阵 m 转换为欧拉角。它呈现 3 个坐标系轴。左边是 m 用作模型视图矩阵，中间是 m 的基向量使用身份模型视图，右边是通过计算的欧拉角构建的模型视图 ...

所有 3 个都应该匹配。如果左边和中间不匹配，那么你得到了不同的矩阵或布局约定。

此处 (10,20,30) [deg] 测试用例预览：

即使经过多次旋转（箭头键）也匹配...

gl_simple.h 可以在这里找到：

PS. 根据 platform/environment 计算可能需要一些边缘情况处理，例如 asin 大于 1，除以零等。atan2 也有其怪癖...

[Edit1] 这里是自动完成所有这些操作的最终 C++ 示例：

//---------------------------------------------------------------------------
enum _euler_cfg_enum
    {
    _euler_cfg_a=0,
    _euler_cfg_b,
    _euler_cfg_c,
    _euler_cfg__sina,
    _euler_cfg_ssina,
    _euler_cfg__sinb_cosa,
    _euler_cfg_ssinb_cosa,
    _euler_cfg__cosb_cosa,
    _euler_cfg_scosb_cosa,
    _euler_cfg__sinc_cosa,
    _euler_cfg_ssinc_cosa,
    _euler_cfg__cosc_cosa,
    _euler_cfg_scosc_cosa,
    _euler_cfgs
    };
//---------------------------------------------------------------------------
void matrix2euler_init(double *e,double *m,int *cfg)    // cross match euler angles e[3] and resulting m[16] transform matrix into cfg[_euler_cfgs]
    {
    int i,j;
    double a,tab[4];
    const double _zero=1e-6;
    for (i=0;i<_euler_cfgs;i++) cfg[i]=-1;      // clear cfg
    // find (+/-)sin(a)
    for (i=0;i<3;i++)                           // test all angles in e[]
        {
        a=sin(e[i]);
        for (j=0;j<16;j++)                      // test all elements in m[]
         if (fabs(fabs(a)-fabs(m[j]))<=_zero)   // find match in |m[j]| = |sin(e[i])|
            {                                   // store configuration
            cfg[_euler_cfg_a]=i;            
            cfg[_euler_cfg__sina]=j;
            cfg[_euler_cfg_ssina]=(a*m[j]<0.0);
            j=-1; break;
            }
        if (j<0){ i=-1; break; }                // stop on match found
        }
    if (i>=0){ cfg[0]=-1; return;   }           // no match !!!
    // find (+/-)???(?)*cos(a)
    a=cos(e[cfg[_euler_cfg_a]]);
    i=0; if (i==cfg[_euler_cfg_a]) i++; tab[0]=sin(e[i])*a; tab[1]=cos(e[i])*a; cfg[_euler_cfg_b]=i;
    i++; if (i==cfg[_euler_cfg_a]) i++; tab[2]=sin(e[i])*a; tab[3]=cos(e[i])*a; cfg[_euler_cfg_c]=i;

    for (i=0;i<4;i++)
        {
        a=tab[i];
        for (j=0;j<16;j++)                      // test all elements in m[]
         if (fabs(fabs(a)-fabs(m[j]))<=_zero)   // find match in |m[j]| = |tab[i]|
            {                                   // store configuration
            cfg[_euler_cfg__sinb_cosa+i+i]=j;
            cfg[_euler_cfg_ssinb_cosa+i+i]=(a*m[j]<0.0);
            j=-1; break;
            }
        if (j>=0){ cfg[0]=-1; return;   }       // no match !!!
        }
    }
//---------------------------------------------------------------------------
void matrix2euler(double *e,double *m,int *cfg) // compute euler angles e[3] from transform matrix m[16] using confing cfg[_euler_cfgs]
    {
    double c;
    //-----angle------         --------------sign--------------     ----------index----------
    e[cfg[_euler_cfg_a]]=asin ((cfg[_euler_cfg_ssina]?-1.0:+1.0) *m[cfg[_euler_cfg__sina     ]]);
    c=cos(e[cfg[_euler_cfg_a]]); if (fabs(c>1e-20)) c=1.0/c; else c=0.0;
    e[cfg[_euler_cfg_b]]=atan2((cfg[_euler_cfg_ssinb_cosa]?-c:+c)*m[cfg[_euler_cfg__sinb_cosa]],
                               (cfg[_euler_cfg_scosb_cosa]?-c:+c)*m[cfg[_euler_cfg__cosb_cosa]]);
    e[cfg[_euler_cfg_c]]=atan2((cfg[_euler_cfg_ssinc_cosa]?-c:+c)*m[cfg[_euler_cfg__sinc_cosa]],
                               (cfg[_euler_cfg_scosc_cosa]?-c:+c)*m[cfg[_euler_cfg__cosc_cosa]]);
    }
//---------------------------------------------------------------------------

用法：

const double deg=M_PI/180.0;
const double rad=180.0/M_PI;
// variables
double e[3],m[16];
int euler_cfg[_euler_cfgs];
// init angles
e[0]=10.0*deg;
e[1]=20.0*deg;
e[2]=30.0*deg;
// compute coresponding rotation matrix
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glRotated(e[0]*rad,1.0,0.0,0.0);
glRotated(e[1]*rad,0.0,1.0,0.0);
glRotated(e[2]*rad,0.0,0.0,1.0);
glGetDoublev(GL_MODELVIEW_MATRIX,m);
// cross match e,m -> euler_cfg
matrix2euler_init(e,m,euler_cfg);

// now we can use
matrix2euler(e,m,euler_cfg);

这适用于任何转换顺序和/或 convention/layout。 init 仅被调用一次，然后您可以将转换用于任何变换矩阵...您还可以根据您的环境的 euler_cfg 结果编写自己的优化版本。

有没有办法从 4x4 矩阵计算 X 和 Y 轴上的 3D 旋转

Is there a way to calculate 3D rotation on X and Y axis from a 4x4 matrix

javascript

math

rotation

matrix

euler-angles