如何编写凯撒密码 Python
How to write a Ceaser Cipher Python
我不知道如何开始编写程序。
input = input("Input the text you would like encrypted")
def cipher_text(letter_code):
for i in input:
number_code = ord(i) + 3
letter_code = chr(number_code)
print(letter_code)
def plain_text(letter_code,regular_text):
for i in input:
regular_text = letter_code - 3
print(regular_text)
print("Encrypted text")
cipher_text()
print("Unencrypted text")
plain_text()
抱歉,我不确定如何开始这个问题。还请指教不给答案
在数学上,如果我们在Caesar cipher
中看到encryption
技术,那么得到加密字母的公式是:
c = (x+n) mod 26,
其中c
是加密字母的位值,x
是实际字母的位值,n
是移位。
同样,对于每个字母decrypt
,我们使用下面给出的公式:
c = (x-n) mod 26
您可以使用我下面的代码来了解如何实现 Caesar Cipher
:
def encrypt(plain_text, s):
encrypted_text = ''
for i in range(len(plain_text)):
if plain_text[i] == ' ':
encrypted_text = encrypted_text + plain_text[i]
elif plain_text[i].isupper():
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-65)%26+65)
else:
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-97)%26+97)
return encrypted_text
def decrypt(encrypt_text, s):
decrypted_text = ''
for i in range(len(encrypt_text)):
if encrypt_text[i] == ' ':
decrypted_text = decrypted_text + encrypt_text[i]
elif encrypt_text[i].isupper():
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-65)%26+65)
else:
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-97)%26+97)
return decrypted_text
plain_text = input("Input the text you would like encrypted:")
s = int(input("Enter shift:"))
encrypt_text = encrypt(plain_text, s)
print("Encrypted text: {}".format(encrypt_text))
print("Decrypted text: {}".format(decrypt(encrypt_text, s)))
示例输出:
Input the text you would like encrypted:Taj Mahal
Enter shift:3
Encrypted text: Wdm Pdkdo
Decrypted text: Taj Mahal
我不知道如何开始编写程序。
input = input("Input the text you would like encrypted")
def cipher_text(letter_code):
for i in input:
number_code = ord(i) + 3
letter_code = chr(number_code)
print(letter_code)
def plain_text(letter_code,regular_text):
for i in input:
regular_text = letter_code - 3
print(regular_text)
print("Encrypted text")
cipher_text()
print("Unencrypted text")
plain_text()
抱歉,我不确定如何开始这个问题。还请指教不给答案
在数学上,如果我们在Caesar cipher
中看到encryption
技术,那么得到加密字母的公式是:
c = (x+n) mod 26,
其中c
是加密字母的位值,x
是实际字母的位值,n
是移位。
同样,对于每个字母decrypt
,我们使用下面给出的公式:
c = (x-n) mod 26
您可以使用我下面的代码来了解如何实现 Caesar Cipher
:
def encrypt(plain_text, s):
encrypted_text = ''
for i in range(len(plain_text)):
if plain_text[i] == ' ':
encrypted_text = encrypted_text + plain_text[i]
elif plain_text[i].isupper():
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-65)%26+65)
else:
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-97)%26+97)
return encrypted_text
def decrypt(encrypt_text, s):
decrypted_text = ''
for i in range(len(encrypt_text)):
if encrypt_text[i] == ' ':
decrypted_text = decrypted_text + encrypt_text[i]
elif encrypt_text[i].isupper():
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-65)%26+65)
else:
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-97)%26+97)
return decrypted_text
plain_text = input("Input the text you would like encrypted:")
s = int(input("Enter shift:"))
encrypt_text = encrypt(plain_text, s)
print("Encrypted text: {}".format(encrypt_text))
print("Decrypted text: {}".format(decrypt(encrypt_text, s)))
示例输出:
Input the text you would like encrypted:Taj Mahal
Enter shift:3
Encrypted text: Wdm Pdkdo
Decrypted text: Taj Mahal