如何编写凯撒密码 Python

How to write a Ceaser Cipher Python

我不知道如何开始编写程序。

input = input("Input the text you would like encrypted")


def cipher_text(letter_code):
    for i in input:
        number_code = ord(i) + 3
        letter_code = chr(number_code)
        print(letter_code)

def plain_text(letter_code,regular_text):
    for i in input:
        regular_text = letter_code - 3
        print(regular_text)
print("Encrypted text")
cipher_text()
print("Unencrypted text")
plain_text()

抱歉,我不确定如何开始这个问题。还请指教不给答案

在数学上,如果我们在Caesar cipher中看到encryption技术,那么得到加密字母的公式是:

c = (x+n) mod 26, 

其中c是加密字母的位值,x是实际字母的位值,n是移位。 同样,对于每个字母decrypt,我们使用下面给出的公式:

c = (x-n) mod 26

您可以使用我下面的代码来了解如何实现 Caesar Cipher:

def encrypt(plain_text, s):
    encrypted_text = ''
    for i in range(len(plain_text)):
        if plain_text[i] == ' ':
            encrypted_text = encrypted_text + plain_text[i]
        elif plain_text[i].isupper():
            encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-65)%26+65)
        else:
            encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-97)%26+97)
    return encrypted_text


def decrypt(encrypt_text, s):
    decrypted_text = ''
    for i in range(len(encrypt_text)):
        if encrypt_text[i] == ' ':
            decrypted_text = decrypted_text + encrypt_text[i]
        elif encrypt_text[i].isupper():
            decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-65)%26+65)
        else:
            decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-97)%26+97)
    return decrypted_text



plain_text = input("Input the text you would like encrypted:")
s = int(input("Enter shift:"))
encrypt_text = encrypt(plain_text, s)
print("Encrypted text: {}".format(encrypt_text))
print("Decrypted text: {}".format(decrypt(encrypt_text, s)))

示例输出:

Input the text you would like encrypted:Taj Mahal

Enter shift:3
Encrypted text: Wdm Pdkdo
Decrypted text: Taj Mahal