在 ionic 4 中创建 sqlite 语句时出错

Question

我正在学习有关 IONIC 4 CRUD 的教程。当我到达 sql 语句时，出现如下错误：

> Argument of type '{}' is not assignable to parameter of type 'any[]'. 
> Type '{}' is missing the following properties from type 'any[]':
> length, pop, push, concat, and 26 more.ts

这是我收到错误的语句：

db.executeSql('CREATE TABLE IF NOT EXISTS expense(rowid INTEGER PRIMARY KEY, date TEXT, type TEXT, description TEXT, amount INT)', {})
db.executeSql('SELECT SUM(amount) AS totalIncome FROM expense WHERE type="Income"', {})
db.executeSql('SELECT SUM(amount) AS totalExpense FROM expense WHERE type="Expense"', {})

我得到“{}”上的红线

这是完整的代码：

getData() {
    this.sqlite.create({
      name: 'ionicdb.db',
      location: 'default'
    }).then((db: SQLiteObject) => {
      db.executeSql('CREATE TABLE IF NOT EXISTS expense(rowid INTEGER PRIMARY KEY, date TEXT, type TEXT, description TEXT, amount INT)', {})
      .then(res => console.log('Executed SQL'))
      .catch(e => console.log(e));
      db.executeSql('SELECT * FROM expense ORDER BY rowid DESC', {})
      .then(res => {
        this.expenses = [];
        for(var i=0; i<res.rows.length; i++) {
          this.expenses.push({rowid:res.rows.item(i)
            .rowid,date:res.rows.item(i).date,type:res.rows.item(i)
            .type,description:res.rows.item(i).description,amount:res.rows.item(i).amount});
        }
      })
      .catch(e => console.log(e));
      db.executeSql('SELECT SUM(amount) AS totalIncome FROM expense WHERE type="Income"', {})
      .then(res => {
        if(res.rows.length>0) {
// tslint:disable-next-line: radix
          this.totalIncome = parseInt(res.rows.item(0).totalIncome);
          this.balance = this.totalIncome - this.totalExpense;
        }
      })
      .catch(e => console.log(e));
      db.executeSql('SELECT SUM(amount) AS totalExpense FROM expense WHERE type="Expense"', {})
      .then(res => {
        if(res.rows.length>0) {
// tslint:disable-next-line: radix
          this.totalExpense = parseInt(res.rows.item(0).totalExpense);
          this.balance = this.totalIncome - this.totalExpense;
        }
      });
    }).catch(e => console.log(e));
  }

我需要你的帮助。谢谢。

Answer 1

你应该通过 [] 而不是 {}。

看看 Ionic Native page example:

db.executeSql('create table danceMoves(name VARCHAR(32))', [])
  .then(() => console.log('Executed SQL'))
  .catch(e => console.log(e));

在 ionic 4 中创建 sqlite 语句时出错

Error when creating an sqlite statement in ionic 4

sqlite

ionic4