PHP curl POST 用于 Watson Video Enrichment
PHP curl POST for Watson Video Enrichment
我正在尝试使用 PHP 7.2 向 Watson Video Enrichment 提交新作业 API。
这是我的代码:
//set some vars for all tasks
$apiUrl = 'https://api-dal.watsonmedia.ibm.com/video-enrichment/v2';
$apiKey = 'xxxxxxxx';
//vars for this task
$path = '/jobs';
$name = 'Test1';
$notification_url = 'https://example.com/notification.php';
$url = 'https://example.com/video.mp4';
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => "simple.custom-model",
"upload" => array(
"url" => $url
)
);
$data_string = json_encode($data);
$ch = curl_init();
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_URL, $apiUrl.$path );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string),
'Authorization: APIKey '.$apiKey
));
$result = curl_exec($ch);
echo $result;
但我无法让它工作,即使使用不同的 CURLOPT,如:
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'POST');
我不断收到回复: Bad Request.
这是 API docs.
我设置的 POST CURL 是不是全错了?我的 $data 数组错了吗?知道如何解决这个问题吗?
阅读他们的 API 文档,字段 preset
似乎不是字符串类型。相反,它有一个定义的架构 here。这看起来类似于您使用 upload
架构的方式。
您应该将数据数组更改为如下所示:
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => array(
"video_url" => "https://example.com/path/to/your/video"
),
"upload" => array(
"url" => $url
)
);
好的,我明白了。感谢@TheGentleman 指路。
我的数据数组应该如下所示:
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => array(
"simple.custom-model" => array(
"video_url" => $url,
"language" => "en-US"
)
),
"upload" => array(
"url" => $url
)
);
我正在尝试使用 PHP 7.2 向 Watson Video Enrichment 提交新作业 API。
这是我的代码:
//set some vars for all tasks
$apiUrl = 'https://api-dal.watsonmedia.ibm.com/video-enrichment/v2';
$apiKey = 'xxxxxxxx';
//vars for this task
$path = '/jobs';
$name = 'Test1';
$notification_url = 'https://example.com/notification.php';
$url = 'https://example.com/video.mp4';
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => "simple.custom-model",
"upload" => array(
"url" => $url
)
);
$data_string = json_encode($data);
$ch = curl_init();
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_URL, $apiUrl.$path );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string),
'Authorization: APIKey '.$apiKey
));
$result = curl_exec($ch);
echo $result;
但我无法让它工作,即使使用不同的 CURLOPT,如:
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'POST');
我不断收到回复: Bad Request.
这是 API docs.
我设置的 POST CURL 是不是全错了?我的 $data 数组错了吗?知道如何解决这个问题吗?
阅读他们的 API 文档,字段 preset
似乎不是字符串类型。相反,它有一个定义的架构 here。这看起来类似于您使用 upload
架构的方式。
您应该将数据数组更改为如下所示:
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => array(
"video_url" => "https://example.com/path/to/your/video"
),
"upload" => array(
"url" => $url
)
);
好的,我明白了。感谢@TheGentleman 指路。
我的数据数组应该如下所示:
$data = array(
"name" => $name,
"notification_url" => $notification_url,
"preset" => array(
"simple.custom-model" => array(
"video_url" => $url,
"language" => "en-US"
)
),
"upload" => array(
"url" => $url
)
);