如何使用 python 从包含括号的字符串中提取子字符串？

Question

我有以下字符串：

The quick brown fox, the cat in the (hat) and the dog in the pound. The Cat in THE (hat):

我需要帮助来提取以下文本：

1) the cat in the (hat)

2) The Cat in THE (hat)

我试过以下方法：

p1 = """The quick brown fox, the cat in the (hat) and the dog in the pound. The Cat in THE (hat)"""
pattern = r'\b{var}\b'.format(var = p1)
with io.open(os.path.join(directory,file), 'r', encoding='utf-8') as textfile:
    for line in textfile:
        result = re.findall(pattern, line)
print (result)

Answer 1

严格匹配那个字符串，你可以使用这个正则表达式。为了将来概括，开头的 (?i) 使其忽略大小写并使用 \ 来转义括号。

import re
regex = re.compile('(?i)the cat in the \(hat\)')
string = 'The quick brown fox, the cat in the (hat) and the dog in the pound. The Cat in THE (hat):'
regex.findall(string)

结果：

['the cat in the (hat)', 'The Cat in THE (hat)']

如何使用 python 从包含括号的字符串中提取子字符串？

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