如何 select * 来自 table 并按单列分组

Question

我想从几个 table 中 select * 但删除重复项而不写出所有列名。合并后的 table 大约有 30 列，我不想把每一列都写出来。

我知道我可以写出所有列名，但我想看看是否有办法用 select *

SELECT
        a.* 

FROM "T1"."T2"."T3" a

LEFT JOIN "T1"."T2"."T4" b on b.id = a.id
LEFT JOIN "T1"."T2"."T5" c on c.id = a.id
LEFT JOIN "T1"."T2"."T6" d on d.id = a.id

WHERE a.org = '123' AND kind = 'abc'

有没有一种方法可以按 a.id 分组，而不必写出每个列的名称？最终 table 中有 41 列，我试图在 id 上仅 return 不同的行。

Answer 1

不完全是 group by，而是 row_number():

SELECT a.*
FROM (SELECT a.*,
             ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY a.id) as seqnum
      FROM "T1"."T2"."T3" a LEFT JOIN
           "T1"."T2"."T4" b 
           ON b.id = a.id LEFT JOIN
           "T1"."T2"."T5" c
           ON c.id = a.id LEFT JOIN
           "T1"."T2"."T6" d 
           ON d.id = a.id
      WHERE a.org = '123' AND kind = 'abc' 
     ) a
WHERE seqnum = 1;

如何 select * 来自 table 并按单列分组

How to select * from table and group by a single column

sql

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