Fatal error: Call to a member function query() on a non-object XAMPP to SQL SERVER 2012

Question

我可以就此事寻求一些指导，我正在 PHP 到 SQL SERVER 上尝试一些测试代码和指南，mysqli 似乎可以与 phpmyadmin 一起正常工作下面的代码，但是，sqlsrv_connect 它似乎不起作用，我知道当涉及到 MSSQL 时有不同的结构，我可以要求 link 或任何来源我可以找到用于连接（或调用从 PHP 到 SQL SERVER 2012 的查询）？

我确实检查了这里提出的所有问题，不幸的是大多数问题都是基于 mysqli 的，我没有看到（或者可能已经跳过）与 SQL SERVER 2012 相关的问题。

我尝试了这个指南 $query = mysqli_query($conn, $sql);，但没有成功。

这是 login.php

的代码

    session_start();
    include 'includes/conn.php';

    if(isset($_POST['login'])){
        $username = $_POST['username'];
        $password = $_POST['password'];
        $sql = "SELECT * FROM usermasterfile WHERE username = '$username'";
        $query = $conn->query($sql);

        if($query->num_rows < 1){
            $_SESSION['error'] = 'Cannot find account with the username';
        }
        else{
            $row = $query->fetch_assoc();
            if(password_verify($password, $row['password'])){
                $_SESSION['admin'] = $row['id'];
            }
            else{
                $_SESSION['error'] = 'Incorrect password';
            }
        }

    }
    else{
        $_SESSION['error'] = 'Input admin credentials first';
    }

    header('location: index.php');

?>

而且，这是 conn.php

的代码

$serverName = "XXXXXX\SQLSERVER";
$connectionInfo = array( "Database"=>"XXXXXX", "UID"=>"XXXXXX", "PWD"=>"xxxxxx");
$conn = sqlsrv_connect( $serverName, $connectionInfo);

if( $conn ) {
     echo "Connection established.<br />";
}else{
     echo "Connection could not be established.<br />";
     die( print_r( sqlsrv_errors(), true));
}
?>

此代码工作文件（用于 phpmyadmin）

    $conn = new mysqli('xxxx', 'xxxx', '', 'xxxx');

    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }

?>

连接建立，但错误依旧

Fatal error: Call to a member function query() on a non-object in C:\xampp\htdocs\path\tofile\login.php on line 9

Answer 1

函数 sqlsrv_* 是 PHP Driver for SQL Server 的一部分，它们不是面向对象的。这就是你错误的原因。

您的 conn.php 似乎是正确的，所以只需在 login.php 中使用适当的 sqlsrv_* 函数即可：

<?
    session_start();
    include 'includes/conn.php';

    if (isset($_POST['login'])) {
        $username = $_POST['username'];
        $password = $_POST['password'];
        $sql = "SELECT * FROM usermasterfile WHERE username = '$username'";
        $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
        if ($query === false ) {
            echo "Error (sqlsrv_query): ".print_r(sqlsrv_errors(), true);
            exit;
        }

        if (sqlsrv_num_rows($query) < 1) {
            $_SESSION['error'] = 'Cannot find account with the username';
        } else {
            $row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC);
            if (password_verify($password, $row['password'])) {
                $_SESSION['admin'] = $row['id'];
            }
            else{
                $_SESSION['error'] = 'Incorrect password';
            }
        }
    }
    else{
        $_SESSION['error'] = 'Input admin credentials first';
    }

    header('location: index.php');
?>

Fatal error: Call to a member function query() on a non-object XAMPP to SQL SERVER 2012

Fatal error: Call to a member function query() on a non-object XAMPP to SQL SERVER 2012

php

sql

sql-server

xampp

sqlsrv