Python: 如何使用正则表达式查找重复的字符串

Question

当在数据块中找到关键字时，我想提取/输出一些数据。如何使用正则表达式检索从第一个“#”到最后一个“)”的所有数据？

//Log_1.txt
# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE 
(some_ID = [12345] reportChange::someMoreInfo called with invalid some ID)

# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE 
(some_ID = [12345] failed::someMoreInfo called with invalid some ID)

代码

import re

with open("Log_1.txt", 'r') as f:
    result = re.search('#(.*)#', f.read())

print(result.group(0))

这不是我的全部代码，但如果关键字是 "reportChange"，输出应该是 >>>

# DON'T WANT #
  .
  .
  .
(some_ID = [12345] reportChange::someMoreInfo called with invalid some ID)

而不是

# DON'T WANT #

Answer 1

假设您想要最新的 # DON'T WANT #，您可以使用正则表达式 #(.*)#[^)]+yourKeyWordHere[^)]+\)。在 python 中，您可以使用字符串格式，并用 {} 代替关键字以替换为您想要的任何单词。

import re

keyword='reportChange'

with open("Log_1.txt", 'r') as f:
    result = re.search('#(.*)#[^)]+{}[^)]+\)'.format(keyword), f.read())

print(result.group(0))

Answer 2

作为正则表达式，您必须使用否定前瞻和否定回顾。

试试这个：(?!#).*(?<![)]) 作为正则表达式。它应该输出 # 和 ).

之间的所有内容

未来：使用 regex101.com 测试您的正则表达式。

Answer 3

此代码仅打印包含 reportChange::someMoreInfo called with invalid some ID:

的数据块

data = '''//Log_1.txt
# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE
(some_ID = [12345] reportChange::someMoreInfo called with invalid some ID)

# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE
(some_ID = [12345] failed::someMoreInfo called with invalid some ID)

# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE
(some_ID = [12345xxx] reportChange::someMoreInfo called with invalid some ID)
'''

import re

for d in re.split(r'\n\n', data):
    g = re.findall(r'^# DON\'T WANT #.*reportChange::someMoreInfo called with invalid some ID\)$', d, flags=re.M|re.DOTALL)
    if g:
        print(g[0])
        print()

打印：

# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE
(some_ID = [12345] reportChange::someMoreInfo called with invalid some ID)

# DON'T WANT #
{12345.54321}
[Tues Jul 2 01:23:45 2019]
< SOME_TYPE
(some_ID = [12345xxx] reportChange::someMoreInfo called with invalid some ID)

Python: 如何使用正则表达式查找重复的字符串

Python: How to use regex to find a repetitive string

regex

recursion

data-extraction

python-3.x