如何展平案例中的序列 class

Question

在 Scala 中，是否可以更有效地使用包含要展开的数组的 case 类的平面图？

这是一个有效但看起来不正确的代码：

object stuff {
    def main(args: Array[String]): Unit = {
        case class Stuff(name: String, stuff: Seq[String])
        case class FlatStuff(name: String, stuff: String)

        val someStuff = Array(Stuff("a", Seq("1", "2", "3")), Stuff("b", Seq("4", "5")))

        val stuffs = someStuff.flatMap(item => {
            val flatten = new Array[FlatStuff](item.stuff.length)
            for (i <- 0 until item.stuff.length) {
                flatten(i) = FlatStuff(item.name, item.stuff(i))
            }
            flatten
        })

        stuffs.foreach(stuff => println(stuff))
    }
}

Answer 1

也许一个简单的理解会更易读：

val stuffs = for {
  Stuff(name, stuffArray) <- someStuff // for each name & struffArray in someStuff.
  stuff <- stuffArray // for each stuff in stuffArray.
} yield FlatStuff(name, stuff) // Return a new FlatSutff.

正如@user6337 在评论中解释的那样，理解只是 map & flatMap.
的语法糖因此，上面可以重写为：

someStuff.flatMap {
  case Stuff(name, stuffArray) =>
    stuffArray.map {
      stuff => FlatStuff(name, stuff)
    }
}

如何展平案例中的序列 class

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