多个 <select> 下拉列表作为 sql 参数 | PHP

Question

我有一个运行代码可以根据 1 <select> 下拉值执行 sql 查询。请问如何使用 2 个或更多 <select> 下拉列表来执行多个查询参数？

例子。我根据 accounttitle 对数据进行了排序，现在我想根据 YEAR(datedue) 对 accountttitle 进行排序，我该怎么做？

这是我目前得到的。

对于isset()

  if(isset($_GET['accounttitle'])){
    $accounttitle = $_GET['accounttitle'];

    $year = date('Y');
  if(isset($_GET['year'])){
    $year = $_GET['year'];
  }
  else "PLEASE SELECT OPTION";
  } 
  ?>

对于<select>

<div class="col-sm-9">
<select class="form-control" id="select_account_title" style="text-transform:uppercase" required>
  <option value="">PLEASE SELECT OPTION</option>
  <?php while ($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)): ?>
    <option value="<?= urlencode($row['accounttitle'])?>"><?= $row['accounttitle'] ?></option>
  <?php endwhile; ?>
</select>
<label>Select Year: </label>
<select class="form-control input-sm" id="select_year">
                      <?php
                        for($i=2013; $i<=2033; $i++){
                          $selected = ($i==$year)?'selected':'';
                          echo "
                            <option value='".$i."' ".$selected.">".$i."</option>
                          ";
                        }
                      ?>
                    </select>
</div>

对于SQL


                    $sql = "SELECT referenceno, employeeidno, accounttitle, 'ON PROGRESS' as debit, postedby, approvedby, notedby, credit FROM earningsamendment where accounttitle= '$accounttitle' and YEAR(datedue)='$year'";
                    $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                    while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){

这是我的担忧。

$(function(){
  $('#select_account_title').change(function(){
    window.location.href = 'earnings_amendment.php?accounttitle='+$(this).val();
  });
});
</script>

如何启用 <script> 读取 2 个参数？喜欢

$(function(){
  $('#select_account_title').change(function(){
    window.location.href = 'earnings_amendment.php?accounttitle='+$(accounttitle).val()'&year='+$(year).val();
  });
});
</script>

或类似的东西？

Answer 1

您需要使用多个选择器进行更改。

$(document).on('change', '#select_account_title, #select_year', function() {
    var account_title = $("#select_account_title").val();
    var year = $("#select_year").val();

    window.location.href = 'earnings_amendment.php?accounttitle='+account_title+'&year='+year;
  });

多个 <select> 下拉列表作为 sql 参数 | PHP

multiple <select> dropdown as sql parameters | PHP

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