从流响应中读取并将其写入另一个响应 Node js

Question

我在主要处理程序中得到了这个：

app.get('/static', (request, response) => {

const id=request.query.id;
const url=endpoint+id;

request({url:url, resolveWithFullResponse: true})
 .then(result => {
 //"result" is a stream response,I want all data from here goes to "response"
 //"result -> "response"
})

主播代码为：

app.get('/getfile', (request, response) =>{
//get the client somewhere
    client.createReadStream()
        }).then(stream => {
            stream.on('end', () => {
                response.end();
            });
            stream.on('error', (error) => {
                response.end();
            });
            stream.pipe(response);
        })
})

我希望 "result" 的所有结果都转到 "response"

Answer 1

如果结果是一个流，你可以简单地使用带有响应的管道，不要忘记添加正确的文件名和内容类型：

request({url:url})
 .then(result => {
   const filename = 'data.json';
   const contentType = 'application/json'
   res.set('Content-disposition', `attachment; filename*=${filename}`); // set a filename for your response f.e. data.json
   res.set(Content-Type', contentType); // set a content type f.e. application/json
   result.pipe(response);
})

注意：如果附加到任意二进制文件，请使用 Content-Type=application/octet-stream

从流响应中读取并将其写入另一个响应 Node js

read from a stream response and write it to another response Node js

node.js

request

request-promise