如何找出变量中有多少行
how to find out how many lines are in a variable
我正在做一个 Telegram 机器人,我想在内联键盘中打印字符串。我有一个可以更改的变量 text
,我想检查变量中有多少行(字符串)可以使用它 0<name<2
并进行限制。怎么做到的?
我可以用 len() 实现,但它告诉我 list index out range
text="head,hand,..."
selectKeyboard = telebot.types.InlineKeyboardMarkup( row_width=1)
if 0<name<2:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name']),callback_data="first")
selectKeyboard.add(one)
if 0<name<3:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
selectKeyboard.add(one,two)
if 0<name<4:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
three = types.InlineKeyboardButton(text=str(text[2]['name']) + " " ,callback_data="three")
selectKeyboard.add(one,two,three)
if 0<name<5:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" "+,callback_data="second")
three = types.InlineKeyboardButton(text=str(text[2]['name']) + " " ,callback_data="three")
four = types.InlineKeyboardButton(text=str(text[3]['name']) + " " , callback_data="four")
selectKeyboard.add(one,two,three,four)
if 0<name<6:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
three = types.InlineKeyboardButton(
text=str(text[2]['name']) + " " ,
callback_data="three")
four = types.InlineKeyboardButton(
text=str(text[3]['name']) + " " ,
callback_data="four")
five=types.InlineKeyboardButton(
text=str(text[4]['name']) + " " ,
callback_data="five")
selectKeyboard.add(one, two, three, four,five)
下面这段代码并没有按照你的想象去做,实际上它只是 return False
,因为 name
是一个 string
而你'重新将它与整数进行比较:
0 < name < 2
相反,您应该测试变量的数量,如下所示:
text = "head,hand,..."
num_vars = len(text.split(','))
if 0 < num_vars < 2:
# same for all the other comparisons
我正在做一个 Telegram 机器人,我想在内联键盘中打印字符串。我有一个可以更改的变量 text
,我想检查变量中有多少行(字符串)可以使用它 0<name<2
并进行限制。怎么做到的?
我可以用 len() 实现,但它告诉我 list index out range
text="head,hand,..."
selectKeyboard = telebot.types.InlineKeyboardMarkup( row_width=1)
if 0<name<2:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name']),callback_data="first")
selectKeyboard.add(one)
if 0<name<3:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
selectKeyboard.add(one,two)
if 0<name<4:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
three = types.InlineKeyboardButton(text=str(text[2]['name']) + " " ,callback_data="three")
selectKeyboard.add(one,two,three)
if 0<name<5:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" "+,callback_data="second")
three = types.InlineKeyboardButton(text=str(text[2]['name']) + " " ,callback_data="three")
four = types.InlineKeyboardButton(text=str(text[3]['name']) + " " , callback_data="four")
selectKeyboard.add(one,two,three,four)
if 0<name<6:
for i in range(len(text)):
one=types.InlineKeyboardButton(text=str(text[0]['name'])+" ",callback_data="first")
two=types.InlineKeyboardButton(text=str(text[1]['name'])+" ",callback_data="second")
three = types.InlineKeyboardButton(
text=str(text[2]['name']) + " " ,
callback_data="three")
four = types.InlineKeyboardButton(
text=str(text[3]['name']) + " " ,
callback_data="four")
five=types.InlineKeyboardButton(
text=str(text[4]['name']) + " " ,
callback_data="five")
selectKeyboard.add(one, two, three, four,five)
下面这段代码并没有按照你的想象去做,实际上它只是 return False
,因为 name
是一个 string
而你'重新将它与整数进行比较:
0 < name < 2
相反,您应该测试变量的数量,如下所示:
text = "head,hand,..."
num_vars = len(text.split(','))
if 0 < num_vars < 2:
# same for all the other comparisons