我如何修改这个 SELECT 查询 return 给我一组包含相同数据的行以获得单行？

Question

我不太喜欢数据库，我正在开发一个在 Oracle 上执行此 SELECT 查询的项目数据库：

 SELECT coda.desc_unita1, coda.pk_coda, coda.stato, coda.fk_tipo_doc, coda.descrizione,         
        coda.num_doc, coda.data_in as data_in, coda.indirizzamento, coda.segnalazione, coda.autorizza , coda.fornitore,
        coda.data_app, coda.motivo_rifiuto, coda.tot_fattura, coda.data_doc, coda.fk_piva_mittente, coda.fk_piva_destinatario    

        FROM (SELECT d.rag_soc1 desc_unita1, a.pk_coda, a.fk_tipo_doc, b.descrizione, a.num_doc,                
                    a.data_in, c.descrizione AS stato, a.indirizzamento, a.segnalazione ,'true' as autorizza,
                    f.rag_soc1 fornitore ,a.data_lavorazione_approvatore data_app,a.motivo_rifiuto,
                    a.tot_fattura,a.data_doc, a.fk_piva_mittente, a.fk_piva_destinatario           
                    FROM coda_rx a, tipo_documenti b, stati c, fornitori d ,aggregazioni e, fornitori f           
                    WHERE a.fk_tipo_doc = b.pk_tipo_doc AND a.fk_piva_mittente = d.pk_piva 
                          AND e.piva_destinatario = f.pk_piva AND a.fk_stato = c.pk_stato
                          AND b.pk_tipo_doc = 9 AND A.CANALE IN ('WEB','BDE')AND A.FK_STATO IN( 12)            
                          AND e.pk_coda_rif = a.pk_coda AND A.NUM_DOC=e.NUM_DOC_PADRE AND e.PIVA_MITTENTE=A.FK_PIVA_DESTINATARIO            
                          AND e.tipo_doc in (0,3) ORDER BY A.PK_CODA) coda

这个查询return给我一些包含所有相同数据的记录（不是一个，而是多个），像这样：

COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000
COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000
COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000
COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000
COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000

如何修改此查询以从先前的 returned 行集中获取单行？因此我需要获取如下内容：

COMPANY SRL 70028   PARKING 9   FATTURA 2222211111  26-MAG-15           true    COMPANY SRL                 01392380547 05779711000

阅读 SQL 文档，在我看来我可以使用 DISTINCT 操作来完成它，还是我遗漏了什么？你能帮我解决这个问题吗？

Answer 1

一个简单的 "group by" 就可以解决问题：

您当前的结果集（快速示例）：

select 'COMPANY SRL' desc_unita1 , 
        70078 as pk_coda,
        'PARKING 9' stato
 from dual 
connect by level < 5 ; 

        DESC_UNITA1    PK_CODA STATO
        ----------- ---------- --------- 
    COMPANY SRL      70078 PARKING 9 
    COMPANY SRL      70078 PARKING 9 
    COMPANY SRL      70078 PARKING 9 
    COMPANY SRL      70078 PARKING 9

添加 GROUP BY 子句：

select desc_unita1,pk_coda,stato
from
(
select 'COMPANY SRL' desc_unita1 , 70078 as pk_coda, 'PARKING 9' stato
from dual
connect by level < 5
)
group by desc_unita1,pk_coda,stato; 

DESC_UNITA1    PK_CODA STATO
----------- ---------- ---------
COMPANY SRL      70078 PARKING 9

这是您期望的结果吗？

我如何修改这个 SELECT 查询 return 给我一组包含相同数据的行以获得单行？

How can I modify this SELECT query that return to me a set of rows that contains the same data to obtain a single row?

sql

database

oracle

distinct

oracle11g