从产品构建中排除特定的子模块

Question

好的，所以我有不同的产品口味和不同的子模块。实现子模块的权利，我这样做：

dependencies {
    implementation fileTree(dir: 'libs', include: ['*.jar'])
    implementation project(path: ':A-Android')
    implementation project(path: ':B-Android')
    implementation project(path: ':C-Android')
}

是否可以仅针对特定产品风味实施子模块 :A-Android？怎么样？

Answer 1

是的，只能为特定风格配置依赖项。这里是 Declare dependencies 文档的摘录：

Declare dependencies

You can configure a dependency for a specific build variant or testing source set by prefixing the name of the build variant or testing source set before the Implementation keyword, as shown in the following example.
dependencies {
    // Adds the local "mylibrary" module as a dependency to the "free" flavor.
    freeImplementation project(":mylibrary")

    // Adds a remote binary dependency only for local tests.
    testImplementation 'junit:junit:4.12'

    // Adds a remote binary dependency only for the instrumented test APK.
    androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.2'
}
For more information, see Add build dependencies.

因此，如果您有 production 和 development 两种口味，那么您可以像这样添加依赖项：

dependencies {
    productionImplementation project(path: ':A-Android')
    DevelopmentImplementation project(path: ':B-Android')

    ..
}

从产品构建中排除特定的子模块

Exclude specific sub-modules from product build

android

android-productflavors