有没有办法在成功加载后延迟发送 Discord 消息？

Question

因此，我尝试创建一个应该在用户离开 Discord 后立即执行的 RichEmbed 消息。在此 RichEmbed 中应该是来自 giphy 的随机 GIF，我使用此节点模块在 getGiphyPic() 函数中创建了它：https://github.com/risan/giphy-random 执行此事件时，将在没有 .setImage() 的情况下发送嵌入。我试过 console.log 并且似乎在成功创建 URL 之前发送了消息。

我已经尝试使事件函数异步并等待图像变量的创建，我还尝试在 giphyRandom 函数之后创建一个 promise，但这似乎并不能解决我的问题。

const Discord = require('discord.js');
const { token, giphyToken } = require('./config.json');
const client = new Discord.Client();
const giphyRandom = require("giphy-random");
  function getGiphyPic() {
    (async () => {

        await giphyRandom(giphyToken, {
            tag: "fail",
            rating: "pg-13"
        }).then(resp => {
            let { data } = resp;

            console.log('Created GiphyURL: ' + JSON.stringify(data.image_url))
            return JSON.stringify(data.image_url);
        });
    })();
};
client.on('guildMemberRemove', async function (member) {

    var logChannel = client.channels.get('60370230389694091');
    if (!logChannel) return;
    var image = await getGiphyPic();
    var  embed = new Discord.RichEmbed()
        .setColor(0xc62828)
        .setAuthor('Someone has left the Server!', member.user.avatarURL);
        .setImage(image);
    logChannel.send(embed).then(message => console.log("Sent message!"));

});

Answer 1

您可以使用提供给您的承诺...

const Discord = require('discord.js');
const { token, giphyToken } = require('./config.json');
const client = new Discord.Client();
const giphyRandom = require("giphy-random");
  function getGiphyPic() {
    return giphyRandom(giphyToken, {
        tag: "fail",
        rating: "pg-13"
    }).then(resp => {
        let { data } = resp;
        console.log('Created GiphyURL: ' + JSON.stringify(data.image_url))
        return data.image_url; // give correct response
    });
};
client.on('guildMemberRemove', function (member) {

    var logChannel = client.channels.get('60370230389694091');
    if (!logChannel) return;
    getGiphyPic().then(image => {
      var  embed = new Discord.RichEmbed()
          .setColor(0xc62828)
          .setAuthor('Someone has left the Server!', member.user.avatarURL);
          .setImage(image);
      logChannel.send(embed).then(message => console.log("Sent message!"));
    });
});

async / await 对于复杂的流控制很有用，但在这里似乎不需要，如果你想使用它，你就太复杂了：

  function getGiphyPic() {
    return giphyRandom(giphyToken, {
            tag: "fail",
            rating: "pg-13"
        }).then(resp => {
            let { data } = resp;

            console.log('Created GiphyURL: ' + JSON.stringify(data.image_url))
            return data.image_url;
        });
  };

只需 return promise 和 async / await 将处理其余部分。

有没有办法在成功加载后延迟发送 Discord 消息？

Is there a way to delay sending a Discord message after something has successfully loaded?

javascript

node.js

giphy-api

discord.js