如何根据 PHP 中的匹配值推送值

Question

$first = [
    ["class" => "1", "type" => "A"],
    ["class" => "2", "type" => "A"],
    ["class" => "3", "type" => "B"]
];

$second = [
    "1" => ["hobbies" => ["A" , "B"] ],
    "2" => ["hobbies" => ["A" ] ],
    "3" => ["hobbies" => [ "C" ] ]
];

说明

第 1 步 => $first 数组我正在存储 class 明智的类型，如 class 1 类型为 A & class 2 类型为 A & class 3 类型为 B
第 2 步 => $second 我正在存储 class 和值的数组键爱好
第 3 步 => $second 数组我想从 $first 数组推送 type 基于class什么是类型

我已经写了 PHP 代码，我也得到了预期的结果，但我是两个 foraech 然后如果条件，我认为这不是正确的编写方式。有什么方法可以优化我的代码吗？

我的代码

foreach ($second as $class => $value) {
    foreach ($first as $key => $temp) {
        if($class == $temp['class'] ){
            $second[$class]['Type'] = $temp['type'];
        }
    }
}
echo "<pre>";
print_r($second);exit;

我的预期答案

Array
(
    [1] => Array
        (
            [hobbies] => Array
                (
                    [0] => A
                    [1] => B
                )

            [Type] => A
        )

    [2] => Array
        (
            [hobbies] => Array
                (
                    [0] => A
                )

            [Type] => A
        )

    [3] => Array
        (
            [hobbies] => Array
                (
                    [0] => C
                )

            [Type] => B
        )

)

Answer 1

由于 $second 中的键与 $first 中的 class 相同，您可以这样做：

foreach ($first as $item) {
    // check if there's a key `$item['class']` in `$second`:
    if (isset($second[$item['class']])) {
        $second[$item['class']]['type'] = $item['type'];
    }
}

此代码将仅使用一个 foreach 超过 $first 数组。

如何根据 PHP 中的匹配值推送值

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