如何将 str 转换为 int

Question

我正在制作一个猜谜游戏，我需要知道如何阻止它按字典顺序排列我的答案，因为这会在我的游戏中造成错误。

我试过 elif Guess < str(value): 而不是 elif Guess < int(value): 但我收到错误消息“'str' 和 'int' 实例之间不支持‘<’ “而且我在其他任何事情上都不走运

这是我正在使用的代码

from random import *
from random import randint
import os

numbers = []
Guesses = []
dif = []

os.system('CLS')
print("I want you to guess my number")
print("\n \n \n \nIf you give up type 'give up' word for word")

f = open("Data.txt", "a")

print("Say 'yes' If You're Ready")

YN = input()



if YN == "yes":
    os.system('cls')
    print("Select a difficulty")
    print('impossible 1 - 10000')
    print('annoying 1 - 1000')
    print('hard 1 - 500')
    print('medium 1 - 200')
    print('easy 1 - 99')
    print('beginner 1 - 10')

diff = input()





if diff == 'easy':
    os.system('CLS')
    value = randint(1, 99)
    numbers.append(value)
    dif.append(diff)

elif diff == 'beginner':
    os.system('CLS')
    value = randint(1, 10)
    numbers.append(value)
    dif.append(diff)

elif diff == 'medium':
    os.system('CLS')
    value = randint(1, 199)
    numbers.append(value)
    dif.append(diff)

elif diff == 'hard':
    os.system('CLS')
    value = randint(1, 499)
    numbers.append(value)
    dif.append(diff)

elif diff == 'annoying':
    os.system('CLS')
    value = randint(1, 1000)
    numbers.append(value)
    dif.append(diff)

elif diff == 'impossible':
    os.system('CLS')
    value = randint(1, 10000)
    numbers.append(value)
    dif.append(diff)


os.system('cls')

while True:
    Guess = input()



    if Guess == "give up":
        print("The Number Was " + str(numbers))
        f.write("------------------------------------------------------------- \n \r")
        f.write("Guesses " + str(Guesses) + "\n \r")
        f.write("Difficulty: " + str(dif) + "\n \r")
        f.write("[USER GAVE UP] \n \r")
        f.write("Correct Answer: " + str(numbers) + "\n \r")
        f.write("------------------------------------------------------------- \n \r")
        break

    elif Guess < str(value):
        print("Higher")
        Guesses.append(Guess + " - Higher")

    elif Guess > str(value):
        print("Lower")
        Guesses.append(Guess + " - Lower")


    elif Guess == str(value):
        os.system('CLS')
        length = len(Guesses)
        f.write("------------------------------------------------------------- \n \r")
        f.write("Guesses " + str(Guesses) + "\n \r")
        f.write("Difficulty: " + str(dif) + "\n \r")
        f.write("Number Of Guesses [" + str(length) + "]\n \r")
        f.write("Correct Answer: " + str(numbers) + "\n \r")
        f.write("------------------------------------------------------------- \n \r")
        print("That Was Correct!")
        for x in Guesses:
            print(x)
        break

input()

Answer 1

您可以尝试将 Guess 从 str 转换为 int，并在整数中进行比较。

elif int(Guess) < value:

Answer 2

正如 maruchen 所说，您应该转换 Guess 变量而不是 value 变量。

但是，仅此一项仍会给您带来问题。用户不必输入整数，实际上应该输入诸如 "give up" 之类的字符串答案。如果您尝试将字符串转换为整数并且该字符串包含非数字，那么您将遇到 ValueError。所以最好是像这样定义一个函数：

def guess_less_than_value(guess, value):
    try:
        return int(guess) < int(value)
    except ValueError:
        return False

那么你可以，但在你的代码主体中：

if guess_less_than_value(Guess, value):
    ....

同样大于。

如何将 str 转换为 int

how to convert str to int

python

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