将选定的 dataTable 行传递到另一个 php 页面中的另一个 dataTable 行

Question

我有这两个table，即table1.php和table2.php

我可以使用这个脚本将数据传递给模态，这个脚本在table1.php中，它可以通过模态将数据传递给table2.php，我现在关心的是如何传递数据直接进入 table2.php 的 SQL 查询？由于它的方式，我只能使用传递给 HTML 元素的模态的数据。有没有办法传递模态值并将其转换为 SQL 查询 PHP?

$(function(){
  $("body").on('click', '.edit', function (e){
    e.preventDefault();
    $('#edit').modal('show');
    var id = $(this).data('id');
    getRow(id);
  });

我正在尝试将选定的数据行传递到另一个 PHP 页面，以便它将成为过滤第二个 PHP table.

的参数

这是我的table1.php

<form type="POST" action="table2.php">
              <table id="example1" class="table table-bordered">
                <thead>
                  <th>Series No.</th>
                  <th>Account Type</th>
                  <th>Tools</th>
                </thead>
                <tbody>
                  <?php
                    $sql = "SELECT * FROM accounttype";
                    $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                    while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){
                      echo "
                        <tr>
                        <td>".$row['seriesno']."</td>
                          <td>".$row['accounttype']."</td>
                          <td>
                            <button class='btn btn-success btn-sm edit btn-flat' data-id='".$row['seriesno']."'><i class='fa fa-edit'></i> Edit</button>
                            <button class='btn btn-danger btn-sm delete btn-flat' data-id='".$row['seriesno']."'><i class='fa fa-trash'></i> Delete</button>
                          </td>
                        </tr>
                      ";
                    }
                  ?>
                </tbody>
              </table>
              </form>

这将是我的 table2.php

<table id="example2" class="table table-bordered">
                <thead>
                  <th>Series No.</th>
                  <th>Account Type</th>
                </thead>
                <tbody>
                  <?php
                    $id=$_POST['seriesno'];
                    $sql = "SELECT * FROM accounttype where seriesno='$id'";
                    $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                    while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){
                      echo "
                        <tr>
                        <td>".$row['seriesno']."</td>
                          <td>".$row['accounttype']."</td>
                        </tr>
                      ";
                    }
                  ?>
                </tbody>
              </table>

问题是table2.php收不到$_POST，好像是什么问题？

编辑：这是我的模态 (table2.php) 我需要的是将数据传递到 table 以便 $id=$_POST['seriesno']; 会起作用。

<div class="modal fade" id="edit">
    <div class="modal-dialog" style="width:100%;">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-label="Close">
                    <span aria-hidden="true">&times;</span></button>
            </div>
            <div class="modal-body">
                    <input type="hidden" class="decid" id="id" name="id">

  <table id="example2" class="table table-bordered">
                <thead>
                  <th>Series No.</th>
                  <th>Account Type</th>
                </thead>
                <tbody>
                  <?php
                    $id=$_POST['seriesno'];
                    $sql = "SELECT * FROM accounttype where seriesno='$id'";
                    $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                    while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){
                      echo "
                        <tr>
                        <td>".$row['seriesno']."</td>
                          <td>".$row['accounttype']."</td>
                        </tr>
                      ";
                    }
                  ?>
                </tbody>
              </table>
            </div>
        </div>
    </div>
</div>

Answer 1

所以.. 问题是您必须在同一页面上提交：并在同一页面中解析模态 window 中的 $_POST 数组，因为它包含在此处。试试这个：

table1.php:

<form method="POST" action="table1.php">
          <table id="example1" class="table table-bordered">
            <thead>
              <th>Series No.</th>
              <th>Account Type</th>
              <th>Tools</th>
            </thead>
            <tbody>
              <?php
                $sql = "SELECT * FROM accounttype";
                $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){
                  echo "
                    <tr>
                    <td>".$row['seriesno']."</td>
                      <td>".$row['accounttype']."</td>
                      <td>
                        <button class='btn btn-success btn-sm edit btn-flat' data-id='".$row['seriesno']."'><i class='fa fa-edit'></i> Edit</button>
                        <button class='btn btn-danger btn-sm delete btn-flat' data-id='".$row['seriesno']."'><i class='fa fa-trash'></i> Delete</button>
                      </td>
                    </tr>
                  ";
                }
              ?>
            </tbody>
          </table>
          </form>

table2.php

<div class="modal fade" id="edit">
    <div class="modal-dialog" style="width:100%;">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-label="Close">
                    <span aria-hidden="true">&times;</span></button>
            </div>
            <div class="modal-body">
                    <input type="hidden" class="decid" id="id" name="id">

  <table id="example2" class="table table-bordered">
                <thead>
                  <th>Series No.</th>
                  <th>Account Type</th>
                </thead>
                <tbody>
                  <?php
                    if(isset($_POST['seriesno'])){
                    $id=$_POST['seriesno'];
                    $sql = "SELECT * FROM accounttype where seriesno='$id'";
                    $query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
                    while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)){
                      echo "
                        <tr>
                        <td>".$row['seriesno']."</td>
                          <td>".$row['accounttype']."</td>
                        </tr>
                      ";
                    }
                    }

                  ?>
                </tbody>
              </table>
            </div>
        </div>
    </div>
</div>

希望它有所帮助

将选定的 dataTable 行传递到另一个 php 页面中的另一个 dataTable 行

Pass selected dataTable row to another dataTable row in another php page

html

php

ajax

jquery

sqlsrv