如何将对齐序列减少到开始和结束坐标?
How to reduce aligned sequences to start and end coordinates?
我有一个数据 table 标记的坐标在两组(A 和 B)之间对齐。例如:
dt_long <- data.table(LABEL_A = c(rep("A", 20), rep("A", 15), rep ("A", 10), rep ("A", 15), rep ("A", 10)),
SEQ_A = c(11:30, 61:75, 76:85, 86:100, 110:119),
LABEL_B= c(rep("C", 20), rep("D", 15), rep("F", 10), rep("G",15), rep("D", 10)),
SEQ_B = c(1:20, 25:11, 16:25, 15:1, 1:5, 8:12))
如何将此信息缩减为短格式,其中给出了每个比对序列的开始和结束坐标。例如:
dt_short <- data.table(LABEL_A = c("A", "A", "A", "A", "A", "A"),
Start_A = c(11, 61, 76, 86, 110, 115),
End_A = c(30, 75, 85, 100, 114, 119),
LABEL_B= c("C", "D", "F", "G", "D", "D"),
Start_B = c(1, 25, 16, 15, 1, 8),
End_B = c(20, 11, 25, 1, 5, 12))
每个比对序列的长度应该相同。例如:
identical(abs(dt_short$End_A - dt_short$Start_A), abs(dt_short$End_B - dt_short$Start_B))
一个直接的方法是按两个标签分组,得到每组的first
和last
,即
library(data.table)
dt_long[, .(Start_A = first(SEQ_A), End_A = last(SEQ_A), Start_B = first(SEQ_B), End_B = last(SEQ_B)), by = .(LABEL_A, LABEL_B)][]
# LABEL_A LABEL_B Start_A End_A Start_B End_B
#1: 1 3 11 30 1 20
#2: 1 4 61 75 25 11
#3: 1 6 76 85 16 25
#4: 1 7 86 100 15 1
我们可以只对 dcast
进行子集化。当有许多不同的列组时也可以无缝工作
dcast(dt_long[, .SD[c(1, .N)], .(LABEL_A, LABEL_B)],
LABEL_A + LABEL_B ~ c("Start", "End")[rowid(LABEL_A, LABEL_B)],
value.var = c("SEQ_A", "SEQ_B"))
# LABEL_A LABEL_B SEQ_A_End SEQ_A_Start SEQ_B_End SEQ_B_Start
#1: 1 3 30 11 20 1
#2: 1 4 75 61 11 25
#3: 1 6 85 76 25 16
#4: 1 7 100 86 1 15
您可以利用 rleid
并结合 Frank 的评论来删除分组列
dt_long[, .(
LABEL_A=LABEL_A[1L], Start_A=SEQ_A[1L], End_A=SEQ_A[.N],
LABEL_B=LABEL_B[1L], Start_B=SEQ_B[1L], End_B=SEQ_B[.N]),
by=rleid(LABEL_A, LABEL_B,
c(0L, cumsum(diff(SEQ_A) > 1L)),
c(0L, cumsum(diff(SEQ_B) > 1L)))][, (1) := NULL]
输出:
LABEL_A Start_A End_A LABEL_B Start_B End_B
1: A 11 30 C 1 20
2: A 61 75 D 25 11
3: A 76 85 F 16 25
4: A 86 100 G 15 1
5: A 110 114 D 1 5
6: A 115 119 D 8 12
我有一个数据 table 标记的坐标在两组(A 和 B)之间对齐。例如:
dt_long <- data.table(LABEL_A = c(rep("A", 20), rep("A", 15), rep ("A", 10), rep ("A", 15), rep ("A", 10)),
SEQ_A = c(11:30, 61:75, 76:85, 86:100, 110:119),
LABEL_B= c(rep("C", 20), rep("D", 15), rep("F", 10), rep("G",15), rep("D", 10)),
SEQ_B = c(1:20, 25:11, 16:25, 15:1, 1:5, 8:12))
如何将此信息缩减为短格式,其中给出了每个比对序列的开始和结束坐标。例如:
dt_short <- data.table(LABEL_A = c("A", "A", "A", "A", "A", "A"),
Start_A = c(11, 61, 76, 86, 110, 115),
End_A = c(30, 75, 85, 100, 114, 119),
LABEL_B= c("C", "D", "F", "G", "D", "D"),
Start_B = c(1, 25, 16, 15, 1, 8),
End_B = c(20, 11, 25, 1, 5, 12))
每个比对序列的长度应该相同。例如:
identical(abs(dt_short$End_A - dt_short$Start_A), abs(dt_short$End_B - dt_short$Start_B))
一个直接的方法是按两个标签分组,得到每组的first
和last
,即
library(data.table)
dt_long[, .(Start_A = first(SEQ_A), End_A = last(SEQ_A), Start_B = first(SEQ_B), End_B = last(SEQ_B)), by = .(LABEL_A, LABEL_B)][]
# LABEL_A LABEL_B Start_A End_A Start_B End_B
#1: 1 3 11 30 1 20
#2: 1 4 61 75 25 11
#3: 1 6 76 85 16 25
#4: 1 7 86 100 15 1
我们可以只对 dcast
进行子集化。当有许多不同的列组时也可以无缝工作
dcast(dt_long[, .SD[c(1, .N)], .(LABEL_A, LABEL_B)],
LABEL_A + LABEL_B ~ c("Start", "End")[rowid(LABEL_A, LABEL_B)],
value.var = c("SEQ_A", "SEQ_B"))
# LABEL_A LABEL_B SEQ_A_End SEQ_A_Start SEQ_B_End SEQ_B_Start
#1: 1 3 30 11 20 1
#2: 1 4 75 61 11 25
#3: 1 6 85 76 25 16
#4: 1 7 100 86 1 15
您可以利用 rleid
并结合 Frank 的评论来删除分组列
dt_long[, .(
LABEL_A=LABEL_A[1L], Start_A=SEQ_A[1L], End_A=SEQ_A[.N],
LABEL_B=LABEL_B[1L], Start_B=SEQ_B[1L], End_B=SEQ_B[.N]),
by=rleid(LABEL_A, LABEL_B,
c(0L, cumsum(diff(SEQ_A) > 1L)),
c(0L, cumsum(diff(SEQ_B) > 1L)))][, (1) := NULL]
输出:
LABEL_A Start_A End_A LABEL_B Start_B End_B
1: A 11 30 C 1 20
2: A 61 75 D 25 11
3: A 76 85 F 16 25
4: A 86 100 G 15 1
5: A 110 114 D 1 5
6: A 115 119 D 8 12