不同后的记录数

Question

我正在使用以下查询进行分页

SELECT * FROM (
  SELECT a.*, rownum row_num FROM (
    select distinct field1, field2, ...
      COUNT(*) OVER () RESULT_COUNT
    from table1
    where condition1
    order by someField desc
  )a 
  WHERE rownum < :maxRow 
)WHERE row_num > = :minRow;

我得到 result_count=294（这是总记录匹配条件），而在 distinct 之后返回的总记录是 61。我怎样才能在 result_count 中得到 61。换句话说，我需要使用 distinct 后的总记录数。

Answer 1

你的意思是这样的

SELECT * FROM (
  SELECT a.*, rownum row_num FROM (
    select field1, field2, ...
      COUNT(DISTINCT field1) OVER () RESULT_COUNT
    from table1
    where condition1
    order by someField desc
  )a 
  WHERE rownum < :maxRow 
)WHERE row_num > = :minRow;

不同后的记录数

Record count after distinct

sql

oracle

count

distinct