不规则多边形的栅格化坐标会改变原始形状
Rasterizing coordinates for an irregular polygon changes original shape
我试图在 R 中平滑不规则多边形的边缘,即将其尖角变成圆边。我正在尝试使用 smoothr::smooth
来执行此操作,但此函数对包 sf
或 sp
中的对象进行操作,而我只有一组坐标。不知何故,将我的 data.frame
变成 SpatialPolygonsDataFrame
对象(包 sp
中的对象 class)的结果是一个矩形,其边界是原始多边形的极限。有谁知道如何在保持原始多边形形状的同时将我的一组坐标转换为 class 与 smoothr::smooth
兼容的对象?这是我所做的,部分遵循 this 页面上的说明:
rm(list=ls()) # my compulsive habit of making sure R's memory is a clean slate
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
plot(0,0,
xlim=c(18.5,19.1), ylim=c(-32.5,-31.6),
xlab="Longitude", ylab="Latitude"
)
polygon(dd[,"Lon"],dd[,"Lat"], border="red")
# To make it smooth I plan on using
library(smoothr)
# But smoothr:: smooth works on objects from packages sf or sp so I need to convert dd.
#convert to spatial points
library(sp)
coordinates(dd) = ~Lon + Lat
# convert to raster
library(raster)
rr <- raster::raster(dd)
#convert raster to polygons
sp = rasterToPolygons(rr, dissolve = T)
map(sp, add=T, col="green", fill=F)
# somehow my irregular polygon turned into a rectangle.
sps <- smooth(sp, method = "ksmooth", smoothness=5)
# this works, but of course is only rounding the corners of sp
map(sps, add=T, col="blue", fill=F)
红色是我来自 data.frame dd
的原始多边形,绿色是对象 sp
,蓝色是 sp
、sps
的平滑版本。函数 smooth
完成了这项工作,问题出在将 dd
转换为 sp
兼容对象的某个地方。我怀疑问题是由 raster()
引起的,但我不确定为什么或如何解决它。
非常感谢。
这里我使用了sf
,因为我个人觉得这样更容易:
library(sf)
library(smoothr)
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
# cast to polygon, use multipoint first though.
polygon <- as.matrix(dd) %>%
sf::st_multipoint() %>%
sf::st_cast("POLYGON")
# smooth polygon
polygon_smoothed <- smoothr::smooth(polygon, method = "ksmooth", smoothness = 0.5)
# plot to check
plot(polygon, col = "red")
plot(polygon_smoothed, col = "blue", add = T)
我在这里找到了另一个解决方案:https://rstudio-pubs-static.s3.amazonaws.com/202536_7a122ff56e9f4062b6b012d9921afd80.html
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
plot(0,0,
xlim=c(18.5,19.1), ylim=c(-32.5,-31.6),
xlab="Longitude", ylab="Latitude"
)
polygon(dd[,"Lon"],dd[,"Lat"], border="red")
library(sp)
p = Polygon(dd)
p2 = Polygons(list(p),1) # I believe this aggregates polygons, so in this case it doesn't do anything.
sp = SpatialPolygons(list(p2))
sps <- smooth(sp, method = "ksmooth", smoothness=0.7)
plot(sps, add=T, border="blue")
我试图在 R 中平滑不规则多边形的边缘,即将其尖角变成圆边。我正在尝试使用 smoothr::smooth
来执行此操作,但此函数对包 sf
或 sp
中的对象进行操作,而我只有一组坐标。不知何故,将我的 data.frame
变成 SpatialPolygonsDataFrame
对象(包 sp
中的对象 class)的结果是一个矩形,其边界是原始多边形的极限。有谁知道如何在保持原始多边形形状的同时将我的一组坐标转换为 class 与 smoothr::smooth
兼容的对象?这是我所做的,部分遵循 this 页面上的说明:
rm(list=ls()) # my compulsive habit of making sure R's memory is a clean slate
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
plot(0,0,
xlim=c(18.5,19.1), ylim=c(-32.5,-31.6),
xlab="Longitude", ylab="Latitude"
)
polygon(dd[,"Lon"],dd[,"Lat"], border="red")
# To make it smooth I plan on using
library(smoothr)
# But smoothr:: smooth works on objects from packages sf or sp so I need to convert dd.
#convert to spatial points
library(sp)
coordinates(dd) = ~Lon + Lat
# convert to raster
library(raster)
rr <- raster::raster(dd)
#convert raster to polygons
sp = rasterToPolygons(rr, dissolve = T)
map(sp, add=T, col="green", fill=F)
# somehow my irregular polygon turned into a rectangle.
sps <- smooth(sp, method = "ksmooth", smoothness=5)
# this works, but of course is only rounding the corners of sp
map(sps, add=T, col="blue", fill=F)
红色是我来自 data.frame dd
的原始多边形,绿色是对象 sp
,蓝色是 sp
、sps
的平滑版本。函数 smooth
完成了这项工作,问题出在将 dd
转换为 sp
兼容对象的某个地方。我怀疑问题是由 raster()
引起的,但我不确定为什么或如何解决它。
非常感谢。
这里我使用了sf
,因为我个人觉得这样更容易:
library(sf)
library(smoothr)
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
# cast to polygon, use multipoint first though.
polygon <- as.matrix(dd) %>%
sf::st_multipoint() %>%
sf::st_cast("POLYGON")
# smooth polygon
polygon_smoothed <- smoothr::smooth(polygon, method = "ksmooth", smoothness = 0.5)
# plot to check
plot(polygon, col = "red")
plot(polygon_smoothed, col = "blue", add = T)
我在这里找到了另一个解决方案:https://rstudio-pubs-static.s3.amazonaws.com/202536_7a122ff56e9f4062b6b012d9921afd80.html
# Example dataset:
dd <- data.frame(
Lon = c(18.95379, 18.82409, 18.58987, 18.80541, 18.92427, 19.00264),
Lat = c(-32.42492, -32.32498, -31.89642, -31.73606, -32.16217, -32.37052)
)
plot(0,0,
xlim=c(18.5,19.1), ylim=c(-32.5,-31.6),
xlab="Longitude", ylab="Latitude"
)
polygon(dd[,"Lon"],dd[,"Lat"], border="red")
library(sp)
p = Polygon(dd)
p2 = Polygons(list(p),1) # I believe this aggregates polygons, so in this case it doesn't do anything.
sp = SpatialPolygons(list(p2))
sps <- smooth(sp, method = "ksmooth", smoothness=0.7)
plot(sps, add=T, border="blue")