考虑 SQL 服务器中所有先前的总和，获取行式总和

Question

考虑到所有先前的总和，尝试获得逐行总和，并得到如下所示的输出。

任何人都可以告诉我我缺少什么吗？

SELECT
  ProductId,
  ProductName,
  ProductAmount As ProductActualAmount,
  CASE
    WHEN (CASE
        WHEN LEAD(ProductAmount) OVER (ORDER BY ProductId) IS NULL THEN 0
        ELSE LEAD(ProductAmount) OVER (ORDER BY ProductId)
      END) != 0.00 THEN (ProductAmount + CASE
        WHEN LAG(ProductAmount) OVER (ORDER BY ProductId) IS NULL THEN 0
        ELSE LAG(ProductAmount) OVER (ORDER BY ProductId)
      END)
    ELSE (CASE
        WHEN LEAD(ProductAmount) OVER (ORDER BY ProductId) IS NULL THEN 0
        ELSE LEAD(ProductAmount) OVER (ORDER BY ProductId)
      END)
  END AS SumAmount
FROM ProductSales

输出：

预期输出：

ProductId   ProductName   ProductActualAmount   SumAmount
---------------------------------------------------------
1           Rexona        35.00                 35.00
2           Liril         40.00                 75.00
3           Dove          45.00                 120.00         
4           Pears         50.00                 170.00

Answer 1

使用 SUM() OVER 将得到您预期的结果：

SELECT ProductId, 
       ProductName,
       ProductAmount AS ProductActualAmount,
       SUM(ProductAmount) OVER (ORDER BY ProductId) AS SumAmount
FROM ProductSales

Demo on db<>fiddle

Answer 2

您还可以使用相关子查询作为

SELECT ProductId, 
       ProductName, 
       ProductAmount AS ProductActualAmount,
       (
         SELECT SUM(PS2.ProductAmount)
         FROM ProductSales PS2
         WHERE PS1.ProductAmount >= PS2.ProductAmount 
       ) SumAmount
FROM ProductSales PS1;

Demo

考虑 SQL 服务器中所有先前的总和，获取行式总和

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