如何使用 AssertJ 验证静态方法抛出异常？

Question

当我尝试测试这个方法时

    static void validatePostcode(final String postcode, final String addressLine)
    {
        if(! hasValidPostcode(postcode, addressLine)) {
            throw new InvalidFieldException("Postcode is null or empty ");
        }
    }

使用以下测试

    @Test
    public void testThrowsAnException()
    {
        assertThatThrownBy(validatePostcode("", "")).isInstanceOf(InvalidFieldException.class);
    }

我在 IntelliJ 中收到此错误消息

assertThatThrownBy (org.assertj.core.api.ThrowableAssert.ThrowingCallable) in Assertions cannot be applied to (void)

与 assertThatExceptionOfType.

相同

是否可以使用 AssertJ 测试静态方法实际上抛出未经检查的异常？我应该在测试中更改什么？

Answer 1

改为这种方式。您需要传递 lambda 以使用 assertj

进行测试

assertThatThrownBy(()->validatePostcode("","")).isInstanceOf(InvalidFieldException.class);

Answer 2

如编译错误所示，该方法需要一个抛出可调用对象。

@Test
public void testThrowsAnException()
{
    assertThatThrownBy(() -> validatePostcode("", "")).isInstanceOf(InvalidFieldException.class);
}

如何使用 AssertJ 验证静态方法抛出异常？

How to verify that static method throws an exception using AssertJ?

java

unit-testing

exception

static

assertj