对 table 进行排序，同时保持行的层次结构

Question

我有一个 table 表示部门的层次结构：

+-----------+--------------+--------------+--------------+-----------+-------+
| Top Dept. | 2-tier Dept. | 3-tire Dept. | 4-tier Dept. |    name   |  tier |
+-----------+--------------+--------------+--------------+-----------+-------+
|        00 |              |              |              |    abc    |   0   |
|           | 00-01        |              |              |    bcd    |   1   |
|           |              | 00-01-01     |              |    cde    |   2   |
|           |              | 00-01-02     |              |    abc    |   2   |
|           | 00-02        |              |              |    aef    |   1   |
|           |              | 00-02-01     |              |    qwe    |   2   |
|           |              | 00-02-03     |              |    abc    |   2   |
|           |              |              | 00-02-03-01  |    abc    |   3   |
+-----------+--------------+--------------+--------------+-----------+-------+

现在我想按名称对同一层中的行进行排序，同时保持整体层次结构，这正是我所期望的：

+-----------+--------------+--------------+--------------+-----------+-------+
| Top Dept. | 2-tier Dept. | 3-tire Dept. | 4-tier Dept. |    name   |  tier |
+-----------+--------------+--------------+--------------+-----------+-------+
|        00 |              |              |              |    abc    |   0   |
|           | 00-02        |              |              |    aef    |   1   |
|           |              | 00-02-03     |              |    abc    |   2   |
|           |              | 00-02-01     |              |    qwe    |   2   |
|           | 00-01        |              |              |    def    |   1   |
|           |              | 00-01-02     |              |    abc    |   2   |
|           |              | 00-01-01     |              |    cde    |   2   |
|           |              |              | 00-02-03-01  |    abc    |   3   |
+-----------+--------------+--------------+--------------+-----------+-------+

缺少数据意味着空，我正在使用 Oracle DB，任何人都可以帮助我吗？
编辑：实际上，它是 this sql 的简单版本，我试图添加一个新列来连接前四列的值，然后按它和名称排序，但它没有用。

Answer 1

更新：这似乎有效...SQL Fiddle

我最初的评论真正需要的是在两个选择中按该顺序将名称修改为部门。这允许引擎首先按名称排序，同时保持层次结构。

WITH cte(Dept, superiorDept, name, depth, sort)AS (
SELECT 
  Dept,
  superiorDept,
  name,
  0,
  name|| dept
FROM hierarchy h
WHERE superiorDept IS NULL

UNION ALL

SELECT 
  h2.Dept,
  h2.superiorDept,
  h2.name,
  cte.depth + 1,
  cte.sort || h2.name ||h2.dept
FROM hierarchy h2
INNER JOIN cte ON h2.superiorDept = cte.Dept
)

SELECT 
  CASE WHEN depth = 0 THEN Dept END AS 一级部门,
  CASE WHEN depth = 1 THEN Dept END AS 二级部门,
  CASE WHEN depth = 2 THEN Dept END AS 三级部门,
  CASE WHEN depth = 3 THEN Dept END AS 四级部门,
  name,
  depth,
  sort
FROM cte
ORDER BY sort, name

对 table 进行排序，同时保持行的层次结构

sort a table while keeping the hierarchy of rows

sql

oracle

sql-order-by