需要通过在XML中找到父节点来改变子节点属性值

Question

我有一个 XML 文件，我需要通过其属性值找到特定的父节点，并相应地更改子节点值

我已经使用下面的代码来做到这一点。但它正在改变父节点的属性值。我知道原因，为什么会发生，但我无法找到解决方案。

import xml.etree.ElementTree as ET
tree=ET.parse("EditedPT.xml")
root = tree.getroot()
for child in root:
    if child.attrib["name"] == "JobStrings":
        child.set("name","Test")
tree.write(open("EditedPT1.xml", 'w'), encoding='unicode')

XML[一个虚拟 XML 文件]

<?xml version="1.0" encoding="UTF-8"?>
<Test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="1">
    <Feature name="Job">
        <Option name="Use"/>
    <Feature>
    <Feature name="Job1">
        <Option name="Use"/>
    <Feature>
</Test>

现在，我需要找到属性 name 为 Job 的节点，并将子节点 Option name="Use" 更改为 Option name=" working"

Answer 1

低于

import xml.etree.ElementTree as ET

xmlstring = '''<?xml version="1.0" encoding="UTF-8"?>
<Test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="1">
    <Feature name="Job">
        <Option name="Use"/>
    </Feature>
    <Feature name="Job1">
        <Option name="Use"/>
    </Feature>
</Test>'''


root = ET.fromstring(xmlstring)
features = root.findall('.//Feature/[@name="Job"]')
for feature in features:
    feature.find('.//Option').attrib['name'] = 'working'

tree_as_str = ET.tostring(root, encoding='utf8', method='xml')
print(tree_as_str)

输出

b'<?xml version=\'1.0\' encoding=\'utf8\'?>\n<Test version="1">\n    <Feature name="Job">\n        <Option name="working" />\n    </Feature>\n    <Feature name="Job1">\n        <Option name="Use" />\n    </Feature>\n</Test>'

需要通过在XML中找到父节点来改变子节点属性值

Need to change the child node attribute value by finding the parent node in XML

python

xml

elementtree

python-3.x