抽屉开关未按预期工作（图标保持不变）

Question

我正在尝试在我的应用程序中实现 ActionBarDrawerToggle，但我做不到。我已经实现了在我的工具栏中显示切换，但图标总是一样的。

这是抽屉关闭时的切换图标：

http://i.stack.imgur.com/HTcom.png

这是打开抽屉的时间：

http://i.stack.imgur.com/dX0Z2.png

如您所见，它并没有从 ic_drawer 变为后退箭头。 ic_drawer 从未显示。

所以，这是我的 activity:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    toolbar = (Toolbar) findViewById(R.id.toolbar);
    setSupportActionBar(toolbar);
    initializeDrawer();
    populateDrawer();
    getSupportActionBar().setDisplayHomeAsUpEnabled(true);
    getSupportActionBar().setHomeButtonEnabled(true);
}

private void initializeDrawer() {
        tagTitles = getResources().getStringArray(R.array.item_names);
        icons = getResources().getStringArray(R.array.item_icons);
        dwLayout = (DrawerLayout) findViewById(R.id.drawer_layout);
        dwList = (ListView) findViewById(R.id.drawer_list);
        dwList.setOnItemClickListener(new DrawerItemClickListener());
        dwToggle = new ActionBarDrawerToggle(this, dwLayout, toolbar, R.string.drawer_open, R.string.drawer_close) {
            public void onDrawerClosed(View view) {
                getSupportActionBar().setTitle("pepe");
                invalidateOptionsMenu();
            }

            public void onDrawerOpened(View drawerView) {
                getSupportActionBar().setTitle("pop");
                invalidateOptionsMenu();
            }
        };
        dwLayout.setDrawerListener(dwToggle);
    }

    private void populateDrawer() {
        ArrayList<DrawerItem> dwItems = new ArrayList<>();
        for (int i = 0; i < tagTitles.length; i++) {
//ignore this; population is not properly working
            dwItems.add(new DrawerItem(tagTitles[i], Resources.getSystem().getIdentifier("abc_ic_menu_copy_mtrl_am_alpha.png", "drawable", getBaseContext().getPackageResourcePath())));
        }

        dwList.setAdapter(new NavigationDrawerAdapter(this, dwItems));
    }

@Override
public void onPostCreate(Bundle savedInstanceState, PersistableBundle persistentState) {
    super.onPostCreate(savedInstanceState, persistentState);
    dwToggle.syncState();
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    int id = item.getItemId();

    if (dwToggle.onOptionsItemSelected(item)) {
        return true;
    }

    if (id == R.id.action_settings) {
        return true;
    }

    return super.onOptionsItemSelected(item);
}

@Override
public void onConfigurationChanged(Configuration newConfig) {
    super.onConfigurationChanged(newConfig);
    dwToggle.onConfigurationChanged(newConfig);
}

private class DrawerItemClickListener implements ListView.OnItemClickListener {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        selectItem(position);
    }
}

谢谢！

Answer 1

使用 DrawerLayout 实例实现以下方法，在您的实例中是 dwLayout。在此行之后执行以下操作

dwLayout.setDrawerListener(dwToggle);

添加这个

drawerLayout.post(new Runnable() {
    @Override
    public void run() {
        // To display hamburger icon in toolbar
        drawerToggle.syncState();
    }
});

或者你也可以这样做

@Override
protected void onPostCreate(Bundle savedInstanceState) {
super.onPostCreate(savedInstanceState);
mDrawerToggle.syncState();
}

抽屉开关未按预期工作（图标保持不变）

Drawer toggle not working as expected (icon remains the same)

android

navigation-drawer

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actionbardrawertoggle