为什么在使用带有结构变体的枚举手动实现的序列化序列化为 TOML 时出现 UnsupportedType 错误?

Why do I get an UnsupportedType error when serializing to TOML with a manually implemented Serialize for an enum with struct variants?

我正在尝试为包含结构变体的枚举实现 Serializeserde.rs documentation 表示如下:

enum E {
    // Use three-step process:
    //   1. serialize_struct_variant
    //   2. serialize_field
    //   3. end
    Color { r: u8, g: u8, b: u8 },

    // Use three-step process:
    //   1. serialize_tuple_variant
    //   2. serialize_field
    //   3. end
    Point2D(f64, f64),

    // Use serialize_newtype_variant.
    Inches(u64),

    // Use serialize_unit_variant.
    Instance,
}

考虑到这一点,我着手实施:

use serde::ser::{Serialize, SerializeStructVariant, Serializer};
use serde_derive::Deserialize;

#[derive(Deserialize)]
enum Variants {
    VariantA,
    VariantB { k: u32, p: f64 },
}

impl Serialize for Variants {
    fn serialize<S>(&self, serializer: S) -> Result<S::Ok, S::Error>
    where
        S: Serializer,
    {
        match *self {
            Variants::VariantA => serializer.serialize_unit_variant("Variants", 0, "VariantA"),
            Variants::VariantB { ref k, ref p } => {
                let mut state =
                    serializer.serialize_struct_variant("Variants", 1, "VariantB", 2)?;
                state.serialize_field("k", k)?;
                state.serialize_field("p", p)?;
                state.end()
            }
        }
    }
}

fn main() {
    let x = Variants::VariantB { k: 5, p: 5.0 };
    let toml_str = toml::to_string(&x).unwrap();
    println!("{}", toml_str);
}

代码可以编译,但是当我 运行 它失败时:

thread 'main' panicked at 'called `Result::unwrap()` on an `Err` value: UnsupportedType', src/libcore/result.rs:999:5
note: Run with `RUST_BACKTRACE=1` environment variable to display a backtrace.

我想问题一定出在我对API的使用上,所以我查阅了APIdocumentation for StructVariant,它看起来和我的代码几乎一样。我确定我遗漏了什么,但根据文档和输出我没有看到它。

TOML 格式不支持具有以下值的枚举:

use serde::Serialize; // 1.0.99
use toml; // 0.5.3

#[derive(Serialize)]
enum A {
    B(i32),
}

fn main() {
    match toml::to_string(&A::B(42)) {
        Ok(s) => println!("{}", s),
        Err(e) => eprintln!("Error: {}", e),
    }
}
Error: unsupported Rust type

不清楚您希望您的数据结构映射到什么作为 TOML。使用 JSON 效果很好:

use serde::Serialize; // 1.0.99
use serde_json; // 1.0.40

#[derive(Serialize)]
enum Variants {
    VariantA,
    VariantB { k: u32, p: f64 },
}

fn main() {
    match serde_json::to_string(&Variants::VariantB { k: 42, p: 42.42 }) {
        Ok(s) => println!("{}", s),
        Err(e) => eprintln!("Error: {}", e),
    }
}
{"VariantB":{"k":42,"p":42.42}}

为枚举启用外部标记使 Serde 能够 serialize/deserialize 它到 TOML:

#[derive(Deserialize)]
#[serde(tag = "type")]
enum Variants {
    VariantA,
    VariantB { k: u32, p: f64 },
}

toml::to_string(&Variants::VariantB { k: 42, p: 13.37 })

序列化为

type = VariantB
k = 42
p = 13.37

这在 Vecs 和 HashMaps 中也很有效。