如何查询数据到JFXComboBox
How to query data into JFXComboBox
我一直在尝试从我的数据库中查询数据并将其作为值
通过我的 JFXComboBox
传递
我尝试将它包装到 while loop
并将每个项目添加到 JFXComboBox
但它仍然没有显示我的数据的价值。
@FXML
JFXComboBox<String> combobox;
@Override
public void initialize(URL url, ResourceBundle resourceBundle) {
String sql = "Select * from transaction_type from transactions";
try(Connection conn = SQLConnection.getConnection(); /*Singleton Class DB Connection*/
Statement statement = conn.createStatement();
ResultSet rs = statement.executeQuery(sql))
{
while(rs.next()){
combobox.getItems.add(rs.getString(2));
}
}
catch(SQLException e)
{
serr(e.getNessage());
}
}
我希望 JFXComboBox
中的项目是在交易中找到的值
它不会执行查询它会由于语法错误而导致错误并抛出异常
String sql = "Select * from transaction_type from transactions";
此查询简化了从交易中获取所有记录的过程
//try this query
String sql = "Select * from transactions";
The correct way is to create a model class, however, I think this can
help you.
创建方法:
public static void fillListFromDataBase (Connection conn, ObservableList<String> list) {
String sql = "SELECT fieldName FROM transactions";
try {
Statement statement = conn.createStatement();
ResultSet rs = statement.executeQuery(sql))
while(rs.next()) {
list.add(rs.getString("fieldName"));
}
} catch(SQLException e) {
e.printStackTrace();
}
}
然后调用方法加载列表中的数据并将列表绑定到Combobox:
JFXComboBox<String> combobox;
private ObservableList<String> list = FXCollections.observableArrayList();
@Override
public void initialize(URL url, ResourceBundle resourceBundle) {
Connection conn = SQLConnection.getConnection();
fillListFromDataBase (conn, list);
combobox.setItems(list);
}
我一直在尝试从我的数据库中查询数据并将其作为值
通过我的JFXComboBox
传递
我尝试将它包装到 while loop
并将每个项目添加到 JFXComboBox
但它仍然没有显示我的数据的价值。
@FXML
JFXComboBox<String> combobox;
@Override
public void initialize(URL url, ResourceBundle resourceBundle) {
String sql = "Select * from transaction_type from transactions";
try(Connection conn = SQLConnection.getConnection(); /*Singleton Class DB Connection*/
Statement statement = conn.createStatement();
ResultSet rs = statement.executeQuery(sql))
{
while(rs.next()){
combobox.getItems.add(rs.getString(2));
}
}
catch(SQLException e)
{
serr(e.getNessage());
}
}
我希望 JFXComboBox
中的项目是在交易中找到的值
它不会执行查询它会由于语法错误而导致错误并抛出异常
String sql = "Select * from transaction_type from transactions";
此查询简化了从交易中获取所有记录的过程
//try this query
String sql = "Select * from transactions";
The correct way is to create a model class, however, I think this can help you.
创建方法:
public static void fillListFromDataBase (Connection conn, ObservableList<String> list) {
String sql = "SELECT fieldName FROM transactions";
try {
Statement statement = conn.createStatement();
ResultSet rs = statement.executeQuery(sql))
while(rs.next()) {
list.add(rs.getString("fieldName"));
}
} catch(SQLException e) {
e.printStackTrace();
}
}
然后调用方法加载列表中的数据并将列表绑定到Combobox:
JFXComboBox<String> combobox;
private ObservableList<String> list = FXCollections.observableArrayList();
@Override
public void initialize(URL url, ResourceBundle resourceBundle) {
Connection conn = SQLConnection.getConnection();
fillListFromDataBase (conn, list);
combobox.setItems(list);
}