如果 UrlFetchApp 出错，muteHttpExceptions 跳转到第 86 行

Question

我希望当出现错误时，脚本会从第 86 行继续。但是当我尝试保存脚本时，它说失败是因为“;”在声明之前。我忘记了什么？


function onOpen( ){
  // This line calls the SpreadsheetApp and gets its UI   
  // Or DocumentApp or FormApp.
  var ui = SpreadsheetApp.getUi();

  //These lines create the menu items and 
  // tie them to functions we will write in Apps Script

  ui.createMenu('Atualizar Clima')
  .addItem('Ativar', 'TudoCompleto')
  .addToUi();
}

function TudoCompleto() {
  var spreadsheet = SpreadsheetApp.getActive();

  //Clima
  spreadsheet.getRange('Monster!A1').activate();
  spreadsheet.getCurrentCell().setFormula('=IMPORTXML(\'Clima\'!F20,"//*[@id=\'page_team_1_block_venue_info_3\']/div/div[1]/dl/dt")');
  spreadsheet.getRange('Clima!F21:F45').activate();
  spreadsheet.getRange('Monster!A1:A25').copyTo(spreadsheet.getActiveRange(), SpreadsheetApp.CopyPasteType.PASTE_VALUES, false);

  //Clima 2
  spreadsheet.getRange('Monster!A1').activate();
  spreadsheet.getCurrentCell().setFormula('=IMPORTXML(\'Clima\'!F20,"//*[@id=\'page_team_1_block_venue_info_3\']/div/div[1]/dl/dd")');
  spreadsheet.getRange('Clima!G21:G44').activate();
  spreadsheet.getRange('Monster!A1:A24').copyTo(spreadsheet.getActiveRange(), SpreadsheetApp.CopyPasteType.PASTE_VALUES, false);

  //CLIMA  
  spreadsheet.getRange('Clima!A3:B8').activate();
  spreadsheet.getActiveRangeList().clear({contentsOnly: true, skipFilteredRows: true});

  var ss = SpreadsheetApp.getActive();
  var sheet = ss.getSheetByName("Clima");
  var apiKey = "c9e1e7816ecc0e8eaeda584109d342bf"; // Or you can try my key

  var cityName = sheet.getRange("A1").getValue();
  // Go to https://openweathermap.org, register and get a free API key
  var apiCall = "api.openweathermap.org/data/2.5/weather?q=" + cityName +"&appid=" + apiKey;

  options = { 'muteHttpExceptions' : true};
  var response = UrlFetchApp.fetch(apiCall, options);
  if (response.cod != "404") {
    var spreadsheet = SpreadsheetApp.getActive();

    var spreadsheet = SpreadsheetApp.getActiveSpreadsheet(); // planilha ativa
    var sheet = spreadsheet.getSheetByName("Clima"); 

    for (var i = 1; i < 10; i++) {

      var cel = "H"+ i //

      if (sheet.getRange(cel).getValue() != "")  {   

        for (var u = 1; i < 1000; u++) {
          var cel2 = "M"+ u //

          if (sheet.getRange(cel2).getValue() == "")  { 

            sheet.getRange("M"+u).setValue(sheet.getRange(cel).getValue());
            break;
          };
        }
      }
    };
    spreadsheet.getRange('Monster!A1').activate();
    spreadsheet.getActiveRangeList().clear({contentsOnly: true, skipFilteredRows: true});
    spreadsheet.getRange('Clima!F16').activate();
    spreadsheet.getActiveRangeList().clear({contentsOnly: true, skipFilteredRows: true});
  }

  var data = JSON.parse(response.getContentText());
  Logger.log(response.getContentText());

  var weather = data["weather"][0]; //It's an array
  var sys = data["sys"];
  var main = data["main"]
  var location = data["name"];
  var country = sys["country"];
  var weatherDesc = weather["main"];
  var temp = main["temp"];
  var minTemp = main["temp_min"];
  var maxTemp = main["temp_max"];

  var weatherData = [
    ["Location:", location],
    ["Country:", country],
    ["Weather:", weatherDesc],
    ["Teaperture:", temp],
    ["Min Temp:", minTemp],
    ["Max Temp:", maxTemp]
  ];

  sheet.getRange(3, 1, weatherData.length, weatherData[0].length).setValues(weatherData);



  //The API Call works
  // The Data will be retrieved like below JSON file.
  //{"coord":{"lon":139,"lat":35},
  //"sys":{"country":"JP","sunrise":1369769524,"sunset":1369821049},
  //"weather":[{"id":804,"main":"clouds","description":"overcast clouds","icon":"04n"}],
  //"main":{"temp":289.5,"humidity":89,"pressure":1013,"temp_min":287.04,"temp_max":292.04},
  //"wind":{"speed":7.31,"deg":187.002},
  //"rain":{"3h":0},
  //"clouds":{"all":92},
  //"dt":1369824698,
  //"id":1851632,
  //"name":"Shuzenji",
  //"cod":200}

  var spreadsheet = SpreadsheetApp.getActive();

  var spreadsheet = SpreadsheetApp.getActiveSpreadsheet(); // planilha ativa
  var sheet = spreadsheet.getSheetByName("Clima"); 

  for (var i = 1; i < 10; i++) {

    var cel = "H"+ i //

    if (sheet.getRange(cel).getValue() != "")  {   

      for (var u = 1; i < 1000; u++) {
        var cel2 = "M"+ u //

        if (sheet.getRange(cel2).getValue() == "")  { 

          sheet.getRange("M"+u).setValue(sheet.getRange(cel).getValue());
          break;
        };
      }
    }
  };
  spreadsheet.getRange('Monster!A1').activate();
  spreadsheet.getActiveRangeList().clear({contentsOnly: true, skipFilteredRows: true});
  spreadsheet.getRange('Clima!F16').activate();
  spreadsheet.getActiveRangeList().clear({contentsOnly: true, skipFilteredRows: true});
}

当我执行它时，它会执行所有操作，但最终会出现一条错误消息，说：

TypeError: Cannot read property '0' of undefined

Answer 1

问题

基本上，这不是 JavaScript（以及基于它的 Google Apps 脚本）的工作方式。 JS 中没有 goto 语句，因此没有跳行（标签语句除外，但它们的使用是有限的）。

解决方案

您需要将第 86 行上实现的逻辑作为一个单独的 function 来重用，并在您的 if 语句中调用它，或者使用新参数重用第 86 行上的代码。

修改点数

response!=404 在你的情况下总是 true 因为 HTTPResponse class 实例永远不会等于整数。查看下面的参考资料，要获取响应代码，您需要调用 getResponseCode() 方法。
此外，如果您要检查是否会发生错误，您应该使用等式比较==而不是不等式!=。

参考

MDN 上的标签声明 reference；
HTTPResponse class reference;

如果 UrlFetchApp 出错，muteHttpExceptions 跳转到第 86 行

muteHttpExceptions jump to line 86 if error in UrlFetchApp

google-sheets

urlfetch

google-apps-script