根据 row_number() 更新列
Update a column based on row_number()
我为我的 table 创建了一个默认值为 0 的新非空列,它会保留显示顺序。我想更新 table 的所有行,displayorder 的值是 row_number() over id ordered。在这里我可以为一个 id 做这个。我如何为所有 ID 执行此操作。
我的 table 是:
id | personid | name | displayorder
---+----------+--------+------------
1 | 10 | test1 | 0
2 | 10 | test2 | 0
3 | 10 | test3 | 0
4 | 10 | test4 | 0
5 | 10 | test5 | 0
6 | 11 | test6 | 0
7 | 11 | test7 | 0
8 | 12 | test8 | 0
我想要的结果是:
id | personid | name | displayorder
---+----------+--------+------------
1 | 10 | test1 | 1
2 | 10 | test2 | 2
3 | 10 | test3 | 3
4 | 10 | test4 | 4
5 | 10 | test5 | 5
6 | 11 | test6 | 1
7 | 11 | test7 | 2
8 | 12 | test8 | 1
这是我的 sql 代码,但它只适用于一个给定的 ID:
update MyTable
set displayorder = z.ord
FROM (
SELECT row_number() over (order by id) as ord, id
FROM MyTable p2
where p2.personid = 1
) z
where MyTable.id= z.id
and personid = 1
一个快速的解决方案是使用排名工具。该示例应该满足您的要求。
DECLARE @Pid TABLE
(
Id INT,
PersonId INT,
Name NVARCHAR(25),
DisplayOrder INT
)
INSERT INTO @Pid
VALUES
(1 , 10 , 'test1',0 ),
(2 , 10 , 'test2',0 ),
(3 , 10 , 'test3',0 ),
(4 , 10 , 'test4',0 ),
(5 , 10 , 'test5',0 ),
(6 , 11 , 'test6',0 ),
(7 , 11 , 'test7',0 ),
(8 , 12 , 'test8',0 )
UPDATE pid
SET DisplayOrder = dpid.rank
FROM @Pid pid
INNER JOIN
(
SELECT *, Rank() OVER(Partition by PersonId Order by Id) as rank
FROM @Pid
)dpid ON dpid.Id = pid.Id
SELECT *
FROM @Pid
如果productproperty
和MyTable
真的一样table,我会这样做:
with cte as (
select
t.displayorder,
row_number() over(partition by t.PersonId order by t.Id) as rn
from MyTable as t
)
update cte set displayorder = rn
这个使用了这样一个事实,即常见的 table 表达式在 SQL 服务器中被视为 updatable 视图。
或者甚至创建视图时使用 row_number()
作为显示顺序,这样它会自动重新计算,因此您不必在每次 add/remove 行时都更新 table。
使用此代码:
Create TABLE #order
(
Id INT,
PersonId INT,
Name NVARCHAR(25),
DisplayOrder INT
)
INSERT INTO #ORDER VALUES(1 , 10 , 'test1',0 )
INSERT INTO #ORDER VALUES(2 , 10 , 'test2',0 )
INSERT INTO #ORDER VALUES(3 , 10 , 'test3',0 )
INSERT INTO #ORDER VALUES(4 , 10 , 'test4',0 )
INSERT INTO #ORDER VALUES(5 , 10 , 'test5',0 )
INSERT INTO #ORDER VALUES(6 , 11 , 'test6',0 )
INSERT INTO #ORDER VALUES(7 , 11 , 'test7',0 )
INSERT INTO #ORDER VALUES(8 , 12 , 'test8',0 )
update #order
Set #order.DisplayOrder=R.DisplayOrder
from(select id,ROW_NUMBER() over (partition by S.personid order by S.id) as DisplayOrder
from #order S) R
where #order.Id=R.id
select * from #order
我为我的 table 创建了一个默认值为 0 的新非空列,它会保留显示顺序。我想更新 table 的所有行,displayorder 的值是 row_number() over id ordered。在这里我可以为一个 id 做这个。我如何为所有 ID 执行此操作。
我的 table 是:
id | personid | name | displayorder
---+----------+--------+------------
1 | 10 | test1 | 0
2 | 10 | test2 | 0
3 | 10 | test3 | 0
4 | 10 | test4 | 0
5 | 10 | test5 | 0
6 | 11 | test6 | 0
7 | 11 | test7 | 0
8 | 12 | test8 | 0
我想要的结果是:
id | personid | name | displayorder
---+----------+--------+------------
1 | 10 | test1 | 1
2 | 10 | test2 | 2
3 | 10 | test3 | 3
4 | 10 | test4 | 4
5 | 10 | test5 | 5
6 | 11 | test6 | 1
7 | 11 | test7 | 2
8 | 12 | test8 | 1
这是我的 sql 代码,但它只适用于一个给定的 ID:
update MyTable
set displayorder = z.ord
FROM (
SELECT row_number() over (order by id) as ord, id
FROM MyTable p2
where p2.personid = 1
) z
where MyTable.id= z.id
and personid = 1
一个快速的解决方案是使用排名工具。该示例应该满足您的要求。
DECLARE @Pid TABLE
(
Id INT,
PersonId INT,
Name NVARCHAR(25),
DisplayOrder INT
)
INSERT INTO @Pid
VALUES
(1 , 10 , 'test1',0 ),
(2 , 10 , 'test2',0 ),
(3 , 10 , 'test3',0 ),
(4 , 10 , 'test4',0 ),
(5 , 10 , 'test5',0 ),
(6 , 11 , 'test6',0 ),
(7 , 11 , 'test7',0 ),
(8 , 12 , 'test8',0 )
UPDATE pid
SET DisplayOrder = dpid.rank
FROM @Pid pid
INNER JOIN
(
SELECT *, Rank() OVER(Partition by PersonId Order by Id) as rank
FROM @Pid
)dpid ON dpid.Id = pid.Id
SELECT *
FROM @Pid
如果productproperty
和MyTable
真的一样table,我会这样做:
with cte as (
select
t.displayorder,
row_number() over(partition by t.PersonId order by t.Id) as rn
from MyTable as t
)
update cte set displayorder = rn
这个使用了这样一个事实,即常见的 table 表达式在 SQL 服务器中被视为 updatable 视图。
或者甚至创建视图时使用 row_number()
作为显示顺序,这样它会自动重新计算,因此您不必在每次 add/remove 行时都更新 table。
使用此代码:
Create TABLE #order
(
Id INT,
PersonId INT,
Name NVARCHAR(25),
DisplayOrder INT
)
INSERT INTO #ORDER VALUES(1 , 10 , 'test1',0 )
INSERT INTO #ORDER VALUES(2 , 10 , 'test2',0 )
INSERT INTO #ORDER VALUES(3 , 10 , 'test3',0 )
INSERT INTO #ORDER VALUES(4 , 10 , 'test4',0 )
INSERT INTO #ORDER VALUES(5 , 10 , 'test5',0 )
INSERT INTO #ORDER VALUES(6 , 11 , 'test6',0 )
INSERT INTO #ORDER VALUES(7 , 11 , 'test7',0 )
INSERT INTO #ORDER VALUES(8 , 12 , 'test8',0 )
update #order
Set #order.DisplayOrder=R.DisplayOrder
from(select id,ROW_NUMBER() over (partition by S.personid order by S.id) as DisplayOrder
from #order S) R
where #order.Id=R.id
select * from #order