Java: 如何对 zip 文件中的多个 xml 文件执行 dos2unix？

Question

我有一个表格可以上传一个 zip 文件，然后将 zip 中的所有 xml 文件转换为 unix 格式（如果它们是 dos 格式）。现在我收到输入作为 InputStream。如何处理输入流中的文件并对其执行 (dos2unix) 以将其转换为 unix 格式？

我尝试将流转换为文件，然后再进行转换，但没有成功

public void uploadFile(UploadAuditConfig transaction,String fileType, InputStream in, String delimiter) {
    ZipInputStream zipInputStream = new ZipInputStream(in);
    ZipEntry entry = null;
    do{
                entry = zipInputStream.getNextEntry();
                //need to convert this entry to unix format if it is dos before I pass it to processFile method
                if(entry != null && !entry.isDirectory()) {
                    List<Map<String,String>> list =processFile(zipInputStream, delimiter);
                    zipInputStream.closeEntry();
                 }
    }while(entry!=null);
}


public List<Map<String, String>> processFile(InputStream in, String 
delimiter){
        List<Map<String,String>> acesList = new ArrayList<>();
        XMLInputFactory xif = XMLInputFactory.newInstance();
        XMLStreamReader xsr = xif.createXMLStreamReader(new InputStreamReader(in));
        while (xsr.nextTag() == XMLStreamConstants.START_ELEMENT) {
        File file = new File("/tmp/" + "out" + i + ".xml");
                FileWriter fw = new FileWriter(file);
                if (!file.exists())
                    file.createNewFile();
                FileOutputStream fos = new FileOutputStream(file, true);
                t.transform(new StAXSource(xsr), new StreamResult(fos));
                fos.close();

                if (i == 0) {
                    JSONObject xmlJSONObjHeader = XML.toJSONObject(content);
                    Object o = JsonPath.parse(xmlJSONObjHeader.toString()).read("$['Header']['BrandAAIAID']");
                    brandaaiaid = String.valueOf(o);
                    logger.info("Brand id: " + brandaaiaid);
                    file.delete();
                    fw.close();
                    i++;


                }
        }
        return acesList;
}

预期：来自输入流的 Unix 格式文件

Answer 1

我能够将输入流转换为文件，然后使用 dos2unix 将文件转换为 unix，然后再次将文件作为输入流传递。

    OutputStream outputStream = null;
    File file1 = new File("/tmp/output.txt");
    try
    {
        outputStream = new FileOutputStream(file1);

        int read = 0;
        byte[] bytes = new byte[1024];
        while ((read = in1.read(bytes)) != -1) {
            outputStream.write(bytes, 0, read);
        }
         } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } finally
        {
            if(outputStream != null)
            { 
            try {
                outputStream.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
    ExecuteShell.executeJavaCommand(file1.getAbsolutePath());

    logger.info("action=output.txt converted from dos to unix");

    InputStream in = null;
    try {
        in = new FileInputStream(file1);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

Java: 如何对 zip 文件中的多个 xml 文件执行 dos2unix？

Java: How to perform dos2unix on multiple xml files in a zip file?

java

inputstream

dos2unix