计算 python grok 中的字符数

Question

有一个任务，我必须输入名字，最后打印出多少个不同的字符和多少个重复字符。

'Your program should read in multiple lines of input, until a blank line is entered. Then it should print out how many unique characters were named, and how many were repeated.'

这是我的结果：

人物：医生
人物：玫瑰
角色：罗里
角色：克拉拉
人物：K-9
角色：大师
角色：博士
人物：艾米
字符：
您命名了 8 个字符
您重复了 1 次

这是我的代码：

count = []   
country = input('Character: ')
a = country.count(country)
b = 0
c = 0
while country:
 count.append(country)
  country = input('Character: ')
  if a == country:
    b = b + 1
  else:
    c = c + 1
c = c - b
count.sort()
print('You named',c,'character(s)')
print('You repeated',a,'time(s)')

应该说：

角色：博士
人物：玫瑰
角色：罗里
角色：克拉拉
人物：K-9
角色：大师
角色：博士
人物：艾米
字符：
您命名了 7 个字符。
您重复了 1 次。

Answer 1

可以使用以下代码段：


n<-ncol(data)

m<-mean(rowMeans(data))

exp_val<-mean(apply(data,1,var))

v<-var(rowMeans(data))-mean(apply(data,1,var))/n

z<-n/(n+exp_val/v)

premiums<-Z*rowMeans(data)+(1-z)*m

Answer 2

country = input('Character: ')

a = country.count(country)
b = 0
c = 0

while country:

 count.append(country)
 country = input('Character: ')
 if country in count:
   b = b + 1
 else:
   c = c + 1

count.sort()
print('You named',c,'character(s)')
print('You repeated',b,'time(s)')

结果：

Character: "AA"
Character: "BB"
Character: "CC"
Character: "BB"
Character: ""
('You named', 3, 'character(s)')
('You repeated', 1, 'time(s)')

主要变化：

 if country in count:     //changed

   c = c - b             //removed

print('You named',c,'character(s)')        //changed
print('You repeated',b,'time(s)')          //changed

Answer 3

您可以将字符和它们的出现次数收集到字典中。（还有 collections.Counter() 是为此而设计的，但为了简单起见，一个普通的 dict 就可以了。）

character_counts = {}

while True:
    character = input("Character: ")
    if not character:  # Empty line?
        break  # Quit the loop
    # Get the current count for the character, or 0 if not found, increment with one,
    # assign back to the dict.
    character_counts[character] = character_counts.get(character, 0) + 1

# Get a list of characters who occur more than once.
repeated_characters = [
    character
    for (character, count) in character_counts.items()
    if count > 1
]

print("You named {} character(s)".format(len(character_counts)))
print("You repeated {} time(s)".format(len(repeated_characters)))

计算 python grok 中的字符数

Counting Characters in python grok

python

grok