如何为 Java Final String 查询正确翻译我的灵活搜索查询?

How can I translate my flexible search query properly for a Java Final String query?

我正在尝试在 Hybris Commerce 上为来自模型的 return 数据创建一个网络服务。我的查询适用于灵活的搜索控制台,但我在 Java 中的方法存在语法问题。

我的灵活搜索查询:

select * from {address as a join customerenvasado as c on {a:owner} = {c:pk}} where {c:rut} like '1754%' 

我的错误:

{"errors": [{
    "message": "type code 'a: owner' invalid",
    "type": "FlexibleSearchError"
}]}

我的函数:

public AddressModel getCustomerEnvasadoForRut(String rut) {
    validateParameterNotNull(rut, "Rut must not be null!");
    final String querys = "SELECT * FROM {a: " + AddressModel._TYPECODE + " as a join " + CustomerEnvasadoModel._TYPECODE + " as c on {a:owner} = {c:pk}} where {c:rut} like ?ParamRut";

    final FlexibleSearchQuery query = new FlexibleSearchQuery(querys);
    query.addQueryParameter("ParamRut", rut);
    List<AddressModel> result = getFlexibleSearchService().<AddressModel>search(querys).getResult();
    if (result != null && !result.isEmpty()) {
        return result.get(0);
    }
    return null;
}

只需按如下方式更改您的查询,它就会起作用:

SELECT {pk} FROM {Address AS a JOIN customerenvasado AS c ON {a:owner} = {c:pk}} WHERE {c:rut} LIKE '1754%'

代替上面给出的查询,您还可以使用以下查询:

SELECT {pk} FROM {Address AS a}, {customerenvasado AS c} WHERE {a:owner} = {c:pk} AND {c:rut} LIKE '1754%'

你的错误在这里:

"SELECT * FROM {a: " + AddressModel._TYPECODE

删除 "a:" 即可。