我想在单击 onTap 时更改作为 ListView 子级的自定义 ListTile 的颜色，并将其他子级颜色设置为默认颜色？

Question

在 Drawer 中，在 listview 中想要在单击 onTap 时更改 CustomListTile 的颜色并将所有其他子项的颜色设置为默认值？

class CustomListTile extends StatelessWidget {

  final Color itemContainerColor;

  const CustomListTile({
    //deafult color is Colors.white
    this.itemContainerColor= Colors.white,
  });

  @override
  Widget build(BuildContext context) {
    return InkWell(
      onTap: (){},

    child: Container(
    margin: EdgeInsets.symmetric(vertical: 4),
    padding: EdgeInsets.symmetric(vertical: 5, horizontal: 16),
    width: 150,
    decoration: BoxDecoration(

        color: itemContainerColor,
       )
    child: 
        Text(
          "ListTile 1",
          style: TextStyle(
              fontSize: 20,
              color: Colors.green,
              fontWeight: FontWeight.w600),
        ),

     ),
   ));
  }
 }

Answer 1

Aakash 只需在选项卡上使用一个布尔值，例如 colorChange = true 当按钮被单击时，其他手在容器的子部件中...

     colorChange ? 
       Text(
         "ListTile 1",
         style: TextStyle(
             fontSize: 20,
             color: Colors.red, // which color you need to use
             fontWeight: FontWeight.w600),
       ): Text(
         "ListTile 2",
         style: TextStyle(
             fontSize: 20,
             color: Colors.green,
             fontWeight: FontWeight.w600),
       )

Answer 2

试试这个。

    class ChangeListViewBGColor extends StatefulWidget {
    _ChangeListViewBGColorState createState() => _ChangeListViewBGColorState();
    }

    class _ChangeListViewBGColorState extends State<ChangeListViewBGColor> {
    final List<String> _listViewData = [
        "Item 1",
        "Item 2",
        "Item 3",
        "Item 4",
        "Item 5",
        "Item 6",
        "Item 7",
        "Item 8",
    ];

    int _selectedIndex = 0;

    _onSelected(int index) {
        setState(() => _selectedIndex = index);
    }

    @override
    Widget build(BuildContext context) {
        return Scaffold(
        appBar: AppBar(
            title: Text('BG change'),
        ),
        body: ListView.builder(
            itemCount: _listViewData.length,
            itemBuilder: (context, index) => Container(
            color: _selectedIndex != null && _selectedIndex == index
                ? Colors.red
                : Colors.white,
            child: ListTile(
                title: CustomListTile(_listViewData[index]),
                onTap: () => _onSelected(index),
            ),
            ),
        ),
        );
    }
    }

    class CustomListTile extends StatelessWidget {

    var titleName;

    CustomListTile(this.titleName);

    @override
    Widget build(BuildContext context) {
        return InkWell(
        child: Container(
            child: Text(
                this.titleName,
                style: TextStyle(
                    fontSize: 20, color: Colors.green, fontWeight: FontWeight.w600),
            ),
            margin: EdgeInsets.symmetric(vertical: 4),
            padding: EdgeInsets.symmetric(vertical: 5, horizontal: 16),
            width: 150,

        )
        );
    }
    }

Answer 3

Note: One can go according to @Amit Prajapati 's solution/logic, but if your use-case is going to get complex over time then I would recommend going as per the below solution.

每当您需要更改元素列表中特定元素的属性时，请使用具有与属性接受的值相同数据类型的值列表长度与主列表中的元素数相同。

在您的情况下，您需要在用户单击特定 ListTile 时更改它的颜色。所以声明一个颜色列表。

List<Color> tileColors;

现在，在主小部件的 initState() 中使用默认值初始化列表（取决于主小部件的长度）。

for(int i=0;i<items.length;i++) tileColors.add(defaultColor);

现在，在使用构建器函数时，使用 tileColors[index]、

设置列表的每个项目 (ListTile)

（我将使用 ListView.builder）

ListView.builder(
itemCount: items.length,
 itemBuilder: (BuildContext context, int index) {
     return new Container(
       color: tileColors[index],
       child: ListTile([...]),
);
    }
)

现在只要用户点击 ListTile 的属性（颜色）值就可以设置状态（）。

ListView.builder(
  itemCount: items.length,
  itemBuilder: (BuildContext context, int index) {
     return new Container(
       color: tileColors[index],
       child: ListTile(
         onTap: (){
            setState((){
          for(int i=0;i<item.length;i++) tileColors[i] = defaultColor;

          tileColors[index] = selectedColor; // selectedColor is the color which you wish to change to.

         // Note: You can add your own conditions over. e.g. If you want the first tile to be of a specific color and the rest should be different color while the user taps.
});
}
),
   );
    }
)

Tip: You can use AnimatedContainer instead of Container widget to create a smooth transition when the user taps. Set the duration parameter to Duration(milliseconds: 300).

我想在单击 onTap 时更改作为 ListView 子级的自定义 ListTile 的颜色，并将其他子级颜色设置为默认颜色？

I want to change the color of CustomListTile which is child of ListView when onTap is clicked, and setting other children color into default one?

flutter

flutter-layout

flutter-animation

flutter-container

flutter-listview