如何使用 JPA 连接 spring 工具套件中具有不同列名的 2 个表?
How to join 2 tables with different column name in spring tool suite with JPA?
是否可以用不同的列名连接 2 table?
这是技能模型 class
@Entity
@Table(name = "x_skill")
public class skillModel {
@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name="biodata_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long biodataId;
@Column(name="skill_name")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String skillName;
@Column(name="skill_level_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long skillLevelId;
@Column(name="is_delete")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private boolean isDelete;
}
这是我的技能水平模型
@Entity
@Table(name = "x_skill_level")
public class SkillLevelModel {
private static final String ALL = null;
@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name="created_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long createdBy;
@Column(name="created_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp createdOn;
@Column(name="modified_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long modifiedBy;
@Column(name="modified_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp modifiedOn;
@Column(name="deleted_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long deletedBy;
@Column(name="deleted_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp deletedOn;
@Column(name="is_delete")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private boolean isDelete;
@Column(name="name")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String name;
@Column(name="description")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String description;
}
我尝试使用加入技能模型:
@ManyToOne
@JoinColumn(name="skill_level_id", referencedColumnName="id", nullable=true, updatable=false, insertable=false)
private SkillModel skm;
但是我得到了java.lang.IllegalArgumentException: Can not set long field com.minipro207.model.SkillModel.deletedBy to null value.
顺便说一句,来自 x_skill_level 的主键在 x_skill 的外键中被命名为 skill_level_id。
谢谢 :)
您需要在第二个实体中添加一个 @OneToMany
,如下所示:
@Entity
@Table(name = "x_skill_level")
public class SkillLevelModel {
// ...
@OneToMany(mappedBy="skm", fetch=FetchType.LAZY)
private List<SkillModel> skills;
// ...
}
@Entity
@Table(name = "x_skill")
public class SkillModel {
// ...
@ManyToOne
@JoinColumn(name="skill_level_id", referencedColumnName="id", nullable=true, updatable=false, insertable=false)
private SkillLevelModel skm;
// ...
}
是否可以用不同的列名连接 2 table? 这是技能模型 class
@Entity
@Table(name = "x_skill")
public class skillModel {
@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name="biodata_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long biodataId;
@Column(name="skill_name")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String skillName;
@Column(name="skill_level_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long skillLevelId;
@Column(name="is_delete")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private boolean isDelete;
}
这是我的技能水平模型
@Entity
@Table(name = "x_skill_level")
public class SkillLevelModel {
private static final String ALL = null;
@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name="created_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long createdBy;
@Column(name="created_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp createdOn;
@Column(name="modified_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long modifiedBy;
@Column(name="modified_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp modifiedOn;
@Column(name="deleted_by")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long deletedBy;
@Column(name="deleted_on")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Timestamp deletedOn;
@Column(name="is_delete")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private boolean isDelete;
@Column(name="name")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String name;
@Column(name="description")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String description;
}
我尝试使用加入技能模型:
@ManyToOne
@JoinColumn(name="skill_level_id", referencedColumnName="id", nullable=true, updatable=false, insertable=false)
private SkillModel skm;
但是我得到了java.lang.IllegalArgumentException: Can not set long field com.minipro207.model.SkillModel.deletedBy to null value.
顺便说一句,来自 x_skill_level 的主键在 x_skill 的外键中被命名为 skill_level_id。 谢谢 :)
您需要在第二个实体中添加一个 @OneToMany
,如下所示:
@Entity
@Table(name = "x_skill_level")
public class SkillLevelModel {
// ...
@OneToMany(mappedBy="skm", fetch=FetchType.LAZY)
private List<SkillModel> skills;
// ...
}
@Entity
@Table(name = "x_skill")
public class SkillModel {
// ...
@ManyToOne
@JoinColumn(name="skill_level_id", referencedColumnName="id", nullable=true, updatable=false, insertable=false)
private SkillLevelModel skm;
// ...
}