如何使用条件从 table 中的 XML 列中选择一个值。 XML 表单包含不同的页面

How do I pick a value from XML column in a table with a condition. XML form contains different page

我有一个 xml 数据列。 XML 数据包含具有不同页眉的表单。每个页面都有无线电类型值。我需要从一页及其值中选择值。

我需要页面主题='Outreach'中的值'id',问题值="Type of Outreach",因为我需要 id="1" 值,而且我还需要来自 Question value="Reason for Assessment" 的 id 值。

下面是示例 xml 数据。

<Test name="Assessment " header="" logoimg="" background="" icon="" firstPage="1" allow_abort="1" is_um="0" is_hidden="0" do_only="1" status="1" locale_id="0" version="74" category_id="150011" maxQuestionID="37" id="10234" force_start="0" user_name=" ggg bbb">
  <PAGE topic="Outreach " progress="5" background="" headerid="" footerid="" flush_concepts="1" lastPage="false" id="1">
    <BRANCH_CONDITION>
      <NEXT_PAGE id="2" />
    </BRANCH_CONDITION>
    <QUESTION value="Type of Outreach " defaultvalue="" style="" tooltip="" read_only="0" usability="5" prefer_concept="0" type="radio" validation="0" id="1" pagename="Outreach ">
      <OPTIONS>
        <OPTION value="Outbound Telephone " id="1" url="" score="0" />
        <OPTION value="Inbound Telephone" id="2" url="" score="0" />
        <OPTION value="In Person" id="3" url="" score="0" />
      </OPTIONS>
    </QUESTION>
    <QUESTION value="Reason for Assessment " defaultvalue="" style="" tooltip="" read_only="0" usability="5" prefer_concept="0" type="radio" validation="0" id="2" pagename="Outreach ">
      <OPTIONS>
        <OPTION value="New" id="1" url="" score="0" />
        <OPTION value="Annual" id="2" url="" score="0" />
        <OPTION value="Triggering Event " id="3" url="" score="0" />
        <OPTION value="LOC Review" id="4" url="" score="0" />
      </OPTIONS>
    </QUESTION>

我尝试了以下 sql。

 SELECT TABLE.META_DATA.value('(/QUESTION//id/node())[1]','int') as outReach
        ,TABLE.META_DATA.value('(/QUESTION//id/node())[1]','int') as ReasonForAssessment
 FROM   Table

以下是我的预期结果

+----------+---------------------+
| Outreach | ReasonForAssessment |
+----------+---------------------+
|     1    |          2          |

几个问题:

  • QUESTION 不是 XML 的根,因此您必须使用 // 或从根向下遍历树:/Test/PAGE/QUESTION/

  • 调整 XPath 以按带有 @ 前缀的属性搜索而不是节点搜索,因为 idQUESTION 的属性(不是子节点)。

  • 调整节点索引[#]为return对应的@id属性值

调整后SQL:

SELECT TABLE.META_DATA.value('(//QUESTION/@id)[1]','int') as outReach
       , TABLE.META_DATA.value('(//QUESTION/@id)[2]','int') as ReasonForAssessment
FROM Table;

-- outReach ReasonForAssessment
--        1                   2

或者对列使用方括号条件:

SELECT TABLE.META_DATA.value('(/Test/PAGE/QUESTION[@value=''Type of Outreach '']/@id)[1]','int') as outReach
        , TABLE.META_DATA.value('(/Test/PAGE/QUESTION[@value=''Reason for Assessment '']/@id)[1]','int') as ReasonForAssessment
FROM Table;

-- outReach ReasonForAssessment
--        1                   2