MongoDB Return 来自数组的内部文档
MongoDB Return Inner Document From Array
我正在尝试从文档中的数组中获取一个元素,但我不想获取整个文档中的元素
我尝试了不同的方法,但他们都return整个文档
db.dept.find({"section.classes.CRN":"1901"}).limit(100)
db.dept.where("section.classes.CRN").eq("1901").limit(100)
json
{
"_id" : ObjectId("5d70ab0c280d6b8ebb850cc1"),
"name" : "Art Studio",
"abbr" : "ARS",
"section" : [
{
"type" : "Undergraduate Courses",
"classes" : [
{
"CRN" : "193",
"Course" : "ARS100",
"Sec" : "01",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
"Days" : "MR",
"Time" : "1230P-0320P",
"Loc" : "SAB 226",
"Instructor" : "Schuck",
"Attributes" : "",
"Avail" : "F"
},
{
"CRN" : "293",
"Course" : "ARS100",
"Sec" : "02",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
"Days" : "MR",
"Time" : "0330P-0620P",
"Loc" : "SAB 226",
"Instructor" : "Itty",
"Attributes" : "",
"Avail" : "F"
},
{...
我在搜索一组 CRN 值时试图得到这个或类似的东西
json
[ {
"CRN" : "193",
"Course" : "ARS100",
"Sec" : "01",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
...
"Instructor" : "Schuck",
"Attributes" : "",
"Avail" : "F"
}
]
db.dept.find({"section.classes.CRN":"1901"},{"section.classes":1}).limit(100)
它在 mongodb 中称为 projection
,您在查找查询中传递第二个对象以指定结果中需要的字段。
所以根据你上面的情况,如果你想要名字,结果中的部分你应该传递这样的东西
db.dept.find({"section.classes.CRN":"1901"},{"name":1, "section":1}).limit(100)
尝试使用聚合管道将双嵌套数组投影为:
输入:
[
{
"_id": ObjectId("5d70ab0c280d6b8ebb850cc1"),
"name": "Art Studio",
"abbr": "ARS",
"section": [
{
"type": "Undergraduate Courses",
"classes": [
{
"CRN": "193",
"Course": "ARS100",
"Sec": "01",
"Title": "Drawing I",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Time": "1230P-0320P",
"Loc": "SAB 226",
"Instructor": "Schuck",
"Attributes": "",
"Avail": "F"
},
{
"CRN": "293",
"Course": "ARS100",
"Sec": "02",
"Title": "Drawing I",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Time": "0330P-0620P",
"Loc": "SAB 226",
"Instructor": "Itty",
"Attributes": "",
"Avail": "F"
}
]
}
]
}
]
查询:
以下展开部分您可以过滤 类 以获得 CRN
db.collection.aggregate([
{
$unwind: "$section"
},
{
$project: {
name: 1,
abbr: 1,
"section.type": 1,
"section.classes": {
$filter: {
input: "$section.classes",
as: "item",
cond: {
$eq: [
"$$item.CRN",
"193"
]
}
}
}
}
},
{
$group: {
_id: "$_id",
section: {
$push: "$section"
}
}
}
])
输出:
您可以根据需要在项目中管理您的密钥,以添加新密钥或替换它们。
[
{
"_id": ObjectId("5d70ab0c280d6b8ebb850cc1"),
"section": [
{
"classes": [
{
"Attributes": "",
"Avail": "F",
"CRN": "193",
"Course": "ARS100",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Instructor": "Schuck",
"Loc": "SAB 226",
"Sec": "01",
"Time": "1230P-0320P",
"Title": "Drawing I"
}
],
"type": "Undergraduate Courses"
}
]
}
]
我正在尝试从文档中的数组中获取一个元素,但我不想获取整个文档中的元素
我尝试了不同的方法,但他们都return整个文档
db.dept.find({"section.classes.CRN":"1901"}).limit(100)
db.dept.where("section.classes.CRN").eq("1901").limit(100)
json
{
"_id" : ObjectId("5d70ab0c280d6b8ebb850cc1"),
"name" : "Art Studio",
"abbr" : "ARS",
"section" : [
{
"type" : "Undergraduate Courses",
"classes" : [
{
"CRN" : "193",
"Course" : "ARS100",
"Sec" : "01",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
"Days" : "MR",
"Time" : "1230P-0320P",
"Loc" : "SAB 226",
"Instructor" : "Schuck",
"Attributes" : "",
"Avail" : "F"
},
{
"CRN" : "293",
"Course" : "ARS100",
"Sec" : "02",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
"Days" : "MR",
"Time" : "0330P-0620P",
"Loc" : "SAB 226",
"Instructor" : "Itty",
"Attributes" : "",
"Avail" : "F"
},
{...
我在搜索一组 CRN 值时试图得到这个或类似的东西
json
[ {
"CRN" : "193",
"Course" : "ARS100",
"Sec" : "01",
"Title" : "Drawing I",
"Cr" : "3",
"Dates" : "8/26-12/19",
...
"Instructor" : "Schuck",
"Attributes" : "",
"Avail" : "F"
}
]
db.dept.find({"section.classes.CRN":"1901"},{"section.classes":1}).limit(100)
它在 mongodb 中称为 projection
,您在查找查询中传递第二个对象以指定结果中需要的字段。
所以根据你上面的情况,如果你想要名字,结果中的部分你应该传递这样的东西
db.dept.find({"section.classes.CRN":"1901"},{"name":1, "section":1}).limit(100)
尝试使用聚合管道将双嵌套数组投影为:
输入:
[
{
"_id": ObjectId("5d70ab0c280d6b8ebb850cc1"),
"name": "Art Studio",
"abbr": "ARS",
"section": [
{
"type": "Undergraduate Courses",
"classes": [
{
"CRN": "193",
"Course": "ARS100",
"Sec": "01",
"Title": "Drawing I",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Time": "1230P-0320P",
"Loc": "SAB 226",
"Instructor": "Schuck",
"Attributes": "",
"Avail": "F"
},
{
"CRN": "293",
"Course": "ARS100",
"Sec": "02",
"Title": "Drawing I",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Time": "0330P-0620P",
"Loc": "SAB 226",
"Instructor": "Itty",
"Attributes": "",
"Avail": "F"
}
]
}
]
}
]
查询: 以下展开部分您可以过滤 类 以获得 CRN
db.collection.aggregate([
{
$unwind: "$section"
},
{
$project: {
name: 1,
abbr: 1,
"section.type": 1,
"section.classes": {
$filter: {
input: "$section.classes",
as: "item",
cond: {
$eq: [
"$$item.CRN",
"193"
]
}
}
}
}
},
{
$group: {
_id: "$_id",
section: {
$push: "$section"
}
}
}
])
输出: 您可以根据需要在项目中管理您的密钥,以添加新密钥或替换它们。
[
{
"_id": ObjectId("5d70ab0c280d6b8ebb850cc1"),
"section": [
{
"classes": [
{
"Attributes": "",
"Avail": "F",
"CRN": "193",
"Course": "ARS100",
"Cr": "3",
"Dates": "8/26-12/19",
"Days": "MR",
"Instructor": "Schuck",
"Loc": "SAB 226",
"Sec": "01",
"Time": "1230P-0320P",
"Title": "Drawing I"
}
],
"type": "Undergraduate Courses"
}
]
}
]