从 OpenAPI 生成 Java Spring API 3

Question

我尝试从 OpenAPI v3 YAML 文件生成 Spring REST 接口。构建说：

Successfully generated code to property(class java.lang.String, property(class java.lang.String, fixed(class java.lang.String, /home/zolv/workspaces/main/generation-test/src/main/java)))

Deprecated Gradle features were used in this build, making it 
incompatible with Gradle 6.0.
Use '--warning-mode all' to show the individual deprecation warnings.
See https://docs.gradle.org/5.5/userguide/command_line_interface.html#sec:command_line_warnings

但是在输出目录中没有生成代码。

我关注了 OpenAPI generator gradle plugin doc 医生。

我的build.gradle:

plugins {
  id 'java-library'
  id "org.openapi.generator" version "4.1.1"
}

repositories {
  jcenter()
}

dependencies {
    implementation "org.openapitools:openapi-generator-gradle-plugin:3.3.4"
}

openApiGenerate {
  generatorName = "spring"
  inputSpec = "$rootDir/docs/openapi/api.yml".toString()
  outputDir = "$rootDir/src/main/java".toString()
  apiPackage = "org.openapi.example.api"
  invokerPackage = "org.openapi.example.invoker"
  modelPackage = "org.openapi.example.model"
  modelFilesConstrainedTo = [
          "Error"
  ]
  configOptions = [
      dateLibrary: "java8"
  ]
}

我的api.yml:

openapi: 3.0.2
info:
  title: API Documentation
  version: 1.0.0
servers:
  - url: http://localhost:8080/
tags:
  - name: Users
paths:
  /users:
    post:
      tags:
        - Users
      summary: Create user
      requestBody:
        content:
          application/json:
            schema:
              $ref: '#/components/schemas/CreateUserRequest'
      responses:
        201:
          description: New user created
          content:
            application/json:
              schema:
                $ref: '#/components/schemas/UserResponse'
components:
  schemas:
    CreateUserRequest:
      title: CreateUserResponse
      required:
        - username
        - password
      type: object
      properties:
        username:
          type: string
          description: Users's username
          example: example@test.com
        password:
          type: string
          description: User's password
          example: $tR0nG_pA55vv0Rd
    UserResponse:
      title: UserResponse
      required:
        - id
        - username
      type: object
      properties:
        id:
          type: string
          description: Users's identifier
          example: "1"
        username:
          type: string
          description: Users's username
          example: example@test.com

api.yml 由生成器正确收集（如果文件中有任何语法错误，构建将失败）。

构建日志显示的内容看起来很可疑：Successfully generated code to property(...。不是说属性包含生成的结果吗？

Gradle版本：

------------------------------------------------------------
Gradle 5.5
------------------------------------------------------------

Build time:   2019-06-28 17:36:05 UTC
Revision:     83820928f3ada1a3a1dbd9a6c0d47eb3f199378f

Kotlin:       1.3.31
Groovy:       2.5.4
Ant:          Apache Ant(TM) version 1.9.14 compiled on March 12 2019
JVM:          11.0.4 (Ubuntu 11.0.4+11-post-Ubuntu-1ubuntu218.04.3)
OS:           Linux 4.15.0-1050-oem amd64

编辑：

我已经检查了来自 gradle plugin 的示例，上面的代码适用于 Gradle v4，但不适用于 5。我仍在调查中。

Answer 1

问题似乎出在 modelFilesConstrainedTo — 它将类限制为 Error。将其注释掉，它将起作用（将生成类）。

但是，还有一个问题：outputDir。根据您的设置，它将生成如下内容：

错了。此外，由于它是 生成的 源，因此不应转到 src/main。更好的替代方法是在 build 目录中生成它，然后将其添加到编译类路径中。看看我为你创建的 the demo 项目，这里是 build.gradle.kts（它几乎像 Groovy）：

plugins {
    id("java-library")
    id("org.openapi.generator").version("4.0.1")
    id("org.springframework.boot").version("2.1.8.RELEASE")
}

repositories {
    jcenter()
}

dependencies {
    implementation("org.springframework.boot:spring-boot-starter-web:2.1.8.RELEASE")
    api("io.springfox:springfox-swagger2:2.8.0")
    api("io.springfox:springfox-swagger-ui:2.8.0")
    api("org.openapitools:jackson-databind-nullable:0.1.0")
}

val spec = "$rootDir/docs/openapi/api.yml"
val generatedSourcesDir = "$buildDir/generated/openapi"

openApiGenerate {
    generatorName.set("spring")

    inputSpec.set(spec)
    outputDir.set(generatedSourcesDir)

    apiPackage.set("org.openapi.example.api")
    invokerPackage.set("org.openapi.example.invoker")
    modelPackage.set("org.openapi.example.model")

    configOptions.set(mapOf(
            "dateLibrary" to "java8"
    ))
}

sourceSets {
    getByName("main") {
        java {
            srcDir("$generatedSourcesDir/src/main/java")
        }
    }
}

tasks {
    val openApiGenerate by getting

    val compileJava by getting {
        dependsOn(openApiGenerate)
    }
}

请注意，您还需要一堆在生成源中使用的依赖项（注释和 Spring 类）。

Answer 2

尝试生成内部源文件夹如下

openApiGenerate {
    generatorName = "spring"
    inputSpec = "$rootDir/src/main/resources/petstore-simple.json".toString()
    outputDir = "$rootDir".toString()
    apiPackage = "com.example.api"
    invokerPackage = "com.example.api"
    modelPackage = "com.example.model"
    configOptions = [
        dateLibrary: "java8"
    ]
    globalProperties = [
            modelDocs: "false"
    ]
    
}

从 OpenAPI 生成 Java Spring API 3

Generate Java Spring API from OpenAPI 3

java

spring

gradle

openapi

openapi-generator