Symfony

Question

我需要过滤这个标签

<div dir=3D"ltr">

我试过了

$crawler = $crawler->filter('div[dir=3D"ltr"]');

但是不行...

Expected "]", but <identifier "D" at 6> found.

有什么想法吗？

Answer 1

            $crawler->filter('div')->each(function (Crawler $node, $i) {
                if ($node->attr('dir') == '3D"ltr"') {
                    // It's the element
                }
            });

这是我所知道的最好的方法。不确定它是否是最好的，但它会起作用。

Answer 2

您正在尝试使用 quoted-printable encoded. You need to decode the data before treating it like HTML. PHP has the built-in function quoted_printable_decode() 的数据来为您执行此操作。

$html = quoted_printable_decode($html);
$crawler = new Crawler($html);
$crawler = $crawler->filter('div[dir="ltr"]');

Symfony - DomCrawler 通过自定义属性获取元素

Symfony - DomCrawler get element by custom attribute

php

dom

domcrawler