如何删除 bash 中的多个匹配项

Question

我有多个具有以下结构的文件：

(Genome1_Sample4A_protein_Genome1_Sample4A_132_2:0.0060449,(Genome1_Sample5A_protein_Genome1_Sample5A_30_12:1e-06,(Genome1_Sample1B_protein_Genome1_Sample1B_99_2:1e-06,Genome1_Sample6A_protein_Genome1_Sample6A_295_2:0.00366292)n2:0.00370314)n1:0.0060449)n0;

我想删除每一个中“_protein”和“:”之间的内容。所以输出如下：

(Genome1_Sample4A:0.0060449,(Genome1_Sample5A:1e-06,(Genome1_Sample1B:1e-06,Genome1_Sample6A:0.00366292)n2:0.00370314)n1:0.0060449)n0;

我尝试过使用 sed 和 awk:

sed -i 's/_protein.*:/:/g' tree1.txt

sed -i 's/_protein.*_[[:digit:]]*:/:/g' tree1.txt

awk '{gsub(/\_protein*:/,":");}1' tree1.txt

但是这些代码中的任何一个都给了我想要的输出。

Answer 1

.* 是 greedy，所以用这个代替：

sed 's/_protein[^:]*:/:/g' tree1.txt

输出：

(Genome1_Sample4A:0.0060449,(Genome1_Sample5A:1e-06,(Genome1_Sample1B:1e-06,Genome1_Sample6A:0.00366292)n2:0.00370314)n1:0.0060449)n0;

如何删除 bash 中的多个匹配项

How to delete multiple matches in bash

bash

awk

sed

non-greedy