在 windows bash 中查找部分字符串

Question

我需要将分支名称中的任务代码添加到每个提交中。我们发现这应该用一个钩子来完成。

代码如下：

#!/bin/bash
# Include any branches for which you wish to disable this script
if [ -z "$BRANCHES_TO_SKIP" ]; then
BRANCHES_TO_SKIP=(master develop)
fi
# Get the current branch name and check if it is excluded
BRANCH_NAME=$(git symbolic-ref --short HEAD)
BRANCH_EXCLUDED=$(printf "%s\n" "${BRANCHES_TO_SKIP[@]}" | grep -c "^$BRANCH_NAME$")
# Trim it down to get the parts we're interested in
TRIMMED=$(echo $BRANCH_NAME | sed -e 's:\([a-z]\+\/\)*\([A-Z]\+-[0-9]\+\).\+::')
# If it isn't excluded, preprend the trimmed branch identifier to the given message
if [ -n "$BRANCH_NAME" ] &&  ! [[ $BRANCH_EXCLUDED -eq 1 ]]; then
sed -i.bak -e "1s,^,$TRIMMED: ," 
fi

现在发生的事情是这样的：

LG-132: LG-132: LG-132: LG-132: LG-132: LG-132: LG-132: Merge branch 'develop' of https://git.dw.com/scm/lg/webapp into develop

所以每次我做修改时都会添加分支代码。现在，我正在尝试检查分支代码是否包含在提交消息中，如果是，则只是 break/return 0.

这是我目前拥有的：

#!/bin/bash
# Include any branches for which you wish to disable this script
if [ -z "$BRANCHES_TO_SKIP" ]; then
  BRANCHES_TO_SKIP=(master develop)
fi
# Get the current branch name and check if it is excluded
BRANCH_NAME=$(git symbolic-ref --short HEAD)
BRANCH_EXCLUDED=$(printf "%s\n" "${BRANCHES_TO_SKIP[@]}" | grep -c "^$BRANCH_NAME$")
# Trim it down to get the parts we're interested in
TRIMMED=$(echo $BRANCH_NAME | sed -e 's:\([a-z]\+\/\)*\([A-Z]\+-[0-9]\+\).\+::')
# If it isn't excluded, preprend the trimmed branch identifier to the given message
if [ -n "$BRANCH_NAME" ] && ! [[ $BRANCH_EXCLUDED -eq 1 ]]; then
  set BRANCH_NAME|find "$TRIMMED" >nul && shouldAddCode=true || shouldAddCode=false
  if $shouldAddCode; then
    echo "test"
  else
    sed -i.bak -e "1s,^,$TRIMMED: ," ""
  fi
fi

我在控制台中得到这个：

find: ‘LG-132’: No such file or directory

现在这段代码行不通了。我正在使用此代码作为参考：

set "i=hello world"
set i|find "world" >nul && set test=yes || set test=no
echo %test%
pause

我错过了什么？

Answer 1

您的参考看起来不像 bash 代码，而是像 CMD 脚本。

要在 bash 脚本中检查某个变量是否以特定字符串开头，规范的方法是 case...esac 构造，例如：

case "$BRANCHNAME" in
"$TRIMMED"*)
  # yes, it's there
  echo "test"
  ;;
*)
  # no, it's not there; add it
  if ! [[ $BRANCH_EXCLUDED -eq 1 ]]; then
    sed -i.bak -e "1s,^,$TRIMMED: ," ""
  fi
  ;;
esac

请注意奇怪的 case arm 语法，它在模式之后只有右括号并以双分号结尾。

Answer 2

最后有点乱，但这是我想出来的

#!/bin/bash
# Include any branches for which you wish to disable this script
if [ -z "$BRANCHES_TO_SKIP" ]; then
  BRANCHES_TO_SKIP=(master develop)
fi
# Get the current branch name and check if it is excluded
BRANCH_NAME=$(git symbolic-ref --short HEAD)
BRANCH_EXCLUDED=$(printf "%s\n" "${BRANCHES_TO_SKIP[@]}" | grep -c "^$BRANCH_NAME$")
# Trim it down to get the parts we're interested in
TRIMMED=$(echo $BRANCH_NAME | sed -e 's:\([a-zA-Z]\+\/\)*\([a-zA-Z]\+-[0-9]\+\).\+::')
TRIMMED=${TRIMMED^^}
# If it isn't excluded, preprend the trimmed branch identifier to the given message
if [ -n "$BRANCH_NAME" ] && ! [[ $BRANCH_EXCLUDED -eq 1 ]]; then
  COMMIT_MESSAGE="$(cat "" | sed -E "s,^#.*|$TRIMMED: *,,g")"
  echo "$COMMIT_MESSAGE" >""
  sed -i.bak -e "1s,^,$TRIMMED: ," ""
fi

在 windows bash 中查找部分字符串

Finding part of string in windows bash

bash

git

shell

githooks