如何在 Swift5 的函数中 运行 'performSegue'？

Question

我是第一个 iPhone 开发者。我的问题是我想在函数中 运行 'performSegue'。在典型的按钮功能中正常工作。但我想在一个函数中完成它。我该怎么办？

@IBAction func nextButtonFuc(_ sender: UIButton) {
       ...
       performSegue(withIdentifier: "moveScreen", sender: self) // it's worked
}

但出现错误

@IBAction func nextButtonFuc(_ sender: UIButton) {
       ...
       networkingCallback(objectvalue!,object,sender)
}
...
func networkingCallback( _ objectvalue: String,_ object: Any,_ send: UIButton) {
      performSegue(withIdentifier: "moveScreen", sender: send) //Error
      self.performSegue(withIdentifier: "moveScreen", sender: self) //Error
      self.performSegue(withIdentifier: "moveScreen", sender: send) //Error
}

我该如何解决这个问题？

performSegue(withIdentifier: "moveScreen", 发件人: 发送)

Error is Implicit use of 'self' in closure; use 'self.' to make capture semantics explicit

self.performSegue(withIdentifier: "moveScreen", sender: send) 错误

Thread 18: signal SIGABRT

提前致谢

Answer 1

当我看到线程相关的错误时，我就在想怎么办。而且我还以为是异步系统导致的错误。于是我通过异步执行解决了问题

DispatchQueue.main.async { self.performSegue(withIdentifier: "makeNickname", sender: self) }